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Q: Why is square root of two an irrational number?

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No. The square root of two is an irrational number. If you multiply the square root of two by the square root of two, you get two which is a rational number.

Yes. For example, the square root of 3 (an irrational number) times the square root of 2(an irrational number) gets you the square root of 6(an irrational number)

The answer to this question confuses me. The square root of two is an irrational number, so obviously if the square root of two is squared it becomes two which is a rational number. Thinking of it that way then the answer is yes, the square of an irrational number can be a rational number. But . . . You had to know beforehand that the irrational number was the square root of another number. If you start out with an irrational number such as Pi you cannot square it because you cannot know the entire number in order to square it.

The square root of 8 is an irrational number because it cannot be represented as a fraction of two integers.

The square root of 31 is an irrational number and so there are no integers for it.

It is an irrational number, which is a kind of real number.

Some square roots of whole numbers are integers, some of them are irrational numbers. The square root of four for instance is a rational number, 2. The square root of two however is an irrational number, approximately 1.414211356.

No. For example, the square root of two plus (minus the square root of two) = 0, which is not an irrational number.

The two square roots are irrational.

The square root of 2 times the square root of 2 is rational.

Usually they are. More specifically, if you take the square root of a positive integer, there are only two possibilities:* If you take the square root of a perfect square, you get a whole number. * In all other cases, you get an irrational number.

The square root of 125 is an irrational number and it is about 11.18 rounded to two decimal places

It can't be expressed as a whole number. The square root of two is irrational, and the product of an irrational number and a rational number is also irrational. So 8*sqrt(2) is irrational.

The sum, or difference, of two irrational numbers can be rational, or irrational. For example, if A = square root of 2 and B = square root of 3, both the sum and difference are irrational. If A = (1 + square root of 2), and B = square root of 2, then, while both are irrational, the difference (equal to 1) is rational.

Yes. It would be 21/2 * 91/2, or "three root two". Root two is an irrational number, so it's products - such as root 18, will be as well.

the square root of 2 fifths of irrational is 0.565685425

The square root of two is an irrational number. Rounded to ten decimal places, it is equal to 1.4142135623.

There is no last digit in the square root of 2. It is an irrational number - and continues forever.

Because no two integer numbers divide to make the number "square root of 7".

That simply isn't true. The sum of two irrational numbers CAN BE rational, but it can also be irrational. As an example, the square root of 2 plus the square root of 2 is irrational.

If the square root of a natural number is not an integer, then it is irrational. Another way to look at it: if a natural number N falls between two perfect squares, then the square root of N is irrational.So in this case, 12 is between 9 (3 squared) and 16 (4 squared). So the square root of 12 is between 3 and 4, and also the square root of 12 is irrational.

No, it is an imaginary number which is a complex number.

No. An irrational number is not expressible as a ratio of two integers. An irrational number has infinite and nonrecurring expansion. An example is pi, or the square root of 2.

Yes

The square root of 110 is an irrational number and so it cannot be any two whole numbers.