Because there is no number of the form x = p/q where p and q are integers such that x-squared = 2.
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No. The square root of two is an irrational number. If you multiply the square root of two by the square root of two, you get two which is a rational number.
The square root of 31 is an irrational number and so there are no integers for it.
The square root of 2 times the square root of 2 is rational.
The sum, or difference, of two irrational numbers can be rational, or irrational. For example, if A = square root of 2 and B = square root of 3, both the sum and difference are irrational. If A = (1 + square root of 2), and B = square root of 2, then, while both are irrational, the difference (equal to 1) is rational.
the square root of 2 fifths of irrational is 0.565685425