It isn't, so the question is pointless.
Actually the most common winning three digit numbers in the Thailand lotto are 231, 453 and 234
Using prime factorization, there are 2 three digit numbers with 9 factors: 512 and 768. There are no three digit numbers with 10 or more prime factors. 512=2^9 and 768=3*2^8
There are no 3 digit numbers between 0 and 9 because 0 and 9 are 1 digit numbers.
If you're asking about distinct prime factors, there are eight numbers tied with three of them. If not, 64 has six twos.
For a 3 digit number, the left most or the most significant digit cannot be zero. So it can be 1,2,3,4,5,6,7,8 or 9 which is 9 possibilities. The middle number can be 0,1,2,3,4,5,6,7,8,9 which is 10 possibilties but one of the digits has been chosen already as the first digit, so the possibilities are only 9. The right most number can be 0,1,2,3,4,5,6,7,8,9 which is 10 possibilities but two of the digits have been already used by the left most and the middle digits. That leaves only 8 possibilities. So the total number of three digit numbers that have three distinct digits is 9 x 9 x 8 = 81 x 8 = 648 possibilities
It would probably be most appropriate to spell out the number. Example: Three hundred years later...
There are 7056 4-digit numbers with at most one of {0,2,4,6,8}, and any number of {1,3,5,7,9}. Leading 0s are not permitted.There are 7056 4-digit numbers with at most one of {0,2,4,6,8}, and any number of {1,3,5,7,9}. Leading 0s are not permitted.There are 7056 4-digit numbers with at most one of {0,2,4,6,8}, and any number of {1,3,5,7,9}. Leading 0s are not permitted.There are 7056 4-digit numbers with at most one of {0,2,4,6,8}, and any number of {1,3,5,7,9}. Leading 0s are not permitted.
93 and 42
By including the number 1000, the digit 1.
In a base ( A ) numbering system, the total number of 4-digit numbers can be calculated by considering that the first digit (most significant) cannot be zero. Therefore, for the first digit, there are ( A - 1 ) options (from 1 to ( A - 1 )), and for each of the remaining three digits, there are ( A ) options (from 0 to ( A - 1 )). Thus, the total number of 4-digit numbers in base ( A ) is given by the formula: ((A - 1) \times A^3).
If you're asking about distinct prime factors, there are eight numbers tied with three of them. If not, 64 has six twos.
the digit 0