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If a rectangle has a perameter of 52cm and width of 12cm what is the length?
Perimeter of a rectangle = 2 x length + 2 x width. 52 = 2l + 2 x 12 = 2l + 24 (Where l is the length) 2l = 52 - 24 = 28 length = 28/2 = 14 cm
How do you find the length and width of rectangle when given the perimeter but not the width or length?
by appying 2l+2w
A rectangle has a perimeter of 52 cm and a width of 12 cm What is the length?
P=2(w)+2(l) 52=2(12)+2(l) 52=24+2l 52-24=2l 28=2l 14=l The length is 14 cm.
How do you find the area and the width when you know the perimeter and the length?
Divide the perimeter by 2 and subtract the length to get the width. Multiply the length by the width to get the area. P=2L+2W P-2L=2W (P/2)-L=W A=LW
Relationship between period and length of a pendulum?
T=1/2l
If a rectangle has a perameter of 52cm and width of 12cm what is the length?
Perimeter of a rectangle = 2 x length + 2 x width. 52 = 2l + 2 x 12 = 2l + 24 (Where l is the length) 2l = 52 - 24 = 28 length = 28/2 = 14 cm
What is the formula for perimeter of a rectangle?
For a rectangle, P = 2L + 2W (L is length, W is width)
Rectangular room has width twice of its length When 6 is decreased from both length and width then its area is differed by 108 so find the width?
The width of the room is equal to twice the Length. Suppose Length = L, width = W, and A = areaW = 2L from the information in the questionNow we know area, A is equal to length times widthW*L=A, plug in 2L for W and we get 2L*L=A or 2L^2=ANext, we see that when 6 is subtracted from both length and width A becomes 108 less.So (2L-6)*(L-6)=A-108Multiply (2L-6)*(L-6) out and the result is (2L^2-18L+36) Set that equal to A-108(2L^2-18L+36)=A-108. We found out that A=2L^2 earlier so we can substitute the terms.(2L^2-18L+36)=2L^2-108. Now solve for LSubtract 2L^2 from both sides(-18L+36)=(-108)Subtract 36 from both sides(-18L)=(-144)Divide by (-18)L=8We know W=2L so W=16Now lets test our answer.16*8=128(16-6)*(8-6)=10*2=20128-20=108So the answer of L=8 and W=16 is correct.
How do you find the length and width of rectangle when given the perimeter but not the width or length?
by appying 2l+2w
A rectangle has a perimeter of 52 cm and a width of 12 cm What is the length?
P=2(w)+2(l) 52=2(12)+2(l) 52=24+2l 52-24=2l 28=2l 14=l The length is 14 cm.
How do you find the area and the width when you know the perimeter and the length?
Divide the perimeter by 2 and subtract the length to get the width. Multiply the length by the width to get the area. P=2L+2W P-2L=2W (P/2)-L=W A=LW
Relationship between period and length of a pendulum?
T=1/2l
What is the formula to find out the perimater of a shape?
2l + 2w or length+width
Why magnetic lentgh is less than geometric length of magnet?
magnetic length refers to the length of magnet which is able to produce magnetic lines from it. since whole length is not able for that magnetic length is small than geometric one
Formula of rectangle?
Area=length x width Perimeter= 2l+2w
The perimeter of a rectangle is 90 cm. If the length is one and one-half times the width Find the length and the width?
Suppose the length is L cm. Then the width, W, is 2L/3 cm. Perimeter = 2(L+W) = 2(L+2L/3) = 10L/3 = 90 cm So L = 27 cm and W = 2L/3 = 18 cm.
How do you write an equation when the perimeter and width are known but the length is needed?
P = perimeter, W = width, L = length P = 2(W + L) = 2W + 2L 2L = P - 2W L = P/2 - W
