All but the number five are multiples of 5.
No, any number with a 5 in one's place would be divisible by 5.
Except for 5, all of them have more than two factors.
32 is an even number (look at the ones place). The only even prime is 2. 95 has 5 as a factor (again look at the ones place). Multiples of 5 have a 0 or 5 in the ones place.That is how you figer out if 32 and 95 in not a prime number.
It is 0. Two of the first 51 prime numbers are 2 and 5, whose product is 10. When you multiply 10 by any other whole numbers, the final digit (in the ones place value) will be 0.
Only one positive prime number has a 5 in the ones digit. That prime number is 5. All other numbers with a 5 in the ones digit are composite because they will be divisible by 5.
It is true (as long as there are no decimal places after the ones place) because those numbers will always be divisible by 2, 5, and 10. With exception of the number zero which is neither prime nor composite.
Since 5 is a prime number, then any number, which is not a multiple of 5, is relatively prime with the number 5. You can determine if a number is a multiple of 5, by looking at the ones place digit. If it is a 0 or 5, and the number itself is not zero, then the number is a multiple of 5.
The ones place in odd numbers will be odd (1, 3, 5, 7, 9)
The possibilities for a digit in the ones place of a prime number greater than 5 are 1, 3, 7, and 9. If a 0, 2, 4, 6, or 8 is in the ones place, the number is divisible by 2, so it would not be prime. If a 5 is in the ones place, the number is divisible by 5, so it would not be prime.
1, 5, and 3
o and 5