The path of this projectile launched from a height y0 has a range d.
In physics, a projectile launched with specific initial conditions in a uniform gravity field will have a predictable range. As in Trajectory of a projectile, we will use:
When neglecting air resistance, the range of a projectile will be
If (y0) is taken to be zero, meaning the object is being launched on flat ground, the range of the projectile will then simplify toso to increase the range θ shoud vary from 0 to 45 and after 45 it starts decreasing.
Yep that is correct. To understand this it may help you to draw a parabola. If you draw a line from the top of the parabola back to the ground you'd notice either side of this line is symmetrical. This isn't quite what happens to a projectile (following a parabolic path), but because of the nature of the question, effects such as air resistance can be ignored. As the projectile approaches the top of its path, the vertical component of its velocity approaches zero. As the projectile begins to fall the magnitude of the vertical component of the projectile begins to increase. The only force that acts on the projectile during flight is gravity which pulls it towards the earth. Since this force and the horizontal component of the projectiles velocity are at right angles to each other, the horizontal component of the velocity is unaffected during flight . This explains the symmetry of the parabola and also means the time to reach the top of path equals the time from the top of path back to the ground. The projectile will hit the ground with the same speed as it left the ground. If you draw a horizontal line through the parabola, at the two points where the line and the parabola cross, the speed of the projectile will be the same. The only change to the balls speed during the flight comes as the vertical component of its velocity tends to zero as it reaches the top of the curve and then falling back down due to gravity. I'm unsure of your physics knowledge but hopefully this doesn't confuse you. If you have learned about vectors, then this can be simply understood/explained.
Increase also.
If the ray is incident at right angles to the reflection surface, angle of Incidence will be 90 degrees and so will be the angle of reflection. In such a case, the incident ray, the normal and the reflected ray coincide.
Uranus does at a 98 degree angle. Pluto also is tilted at a 122 degree angle.
the unit used to measure angle is degree. It is also measured in radians.
55
Suppose a projectile is fired from a gun, we know that "g" remains constant and as we use horizontal component of velocity in range sov0 also remains constant. Only sin2θ responsible for change in range. The range will be maximum if sin2θ has its maximum value that is 1.for maximum range:sin2θ = 12θ = sin-1 (1)θ = 90/2θ = 45 (degree)therefor if projectile is projected with the angle of 45(degree) its range will be maximum.
It will also increase.
Theoretically, ignoring air friction, 45 degrees. But that also depends on muzzle velocity. If you can fire a projectile at a speed great enough, it would become an orbiting 'satellite' if fired parallel to the ground.
A: The pitch angle is a speed factor and also a torque factor. Increasing or decreasing the angle will effect these factors inversely
The values of the range also tend to increase.
The weight of a trebuchet affects the distance the ball will travel because it determines the amount of kinetic energy that can be transferred to the projectile. A heavier trebuchet will have more potential energy, which, when released, will result in a greater velocity and thus a longer distance for the ball to travel. However, other factors, such as the counterweight position and design, also play a role in determining the range of the projectile.
No because each interior angle increases in size whereas each exterior angle decreases in size.
The blank. You might also say dummy munitions, which are shaped to resemble a cartridge with a projectile, but have no actual projectile.
It depends on many ballistic and environmental factors such as size, weight, shape of the projectile. also environmental factors such as ballistic density, air temp, location of where you are in relation to the poles or equator. Also the type of material the projectile and rifiling such as how many twists and the angle of twist. there is also powder temperature, powder density and propellant type that will also affect the muzzle velocity, also how many rounds that were fired as more rounds equal greater wear and less speed... wind speed and direction also factors into the ballistics. <><><><> Above is technically correct- short answer is MOST bullets reach their maximum range when fired with the line of the bore raised to 41-45 degrees above the horizontal.
They increase also The interior angles of a polygon with 'n' sides add up to = 180(n-2) So each angle measures 180(n-2) ÷ n.
yes it does because you can get the maximum distance from a 45 degree angle - at an elevation of 0, but as your beginning height (above the surface) increases the angle for maximum range changes.