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What unit of measure would you use to measure a pair of sunglasses?
UV
What method would you use to prove that segment UV is congruent to segment WV?
If V is the midpoint of the segment UW, then you would use the Definition of a Midpoint, which states that two congruent segments are created.
How can you use a discriminant to write an equation that has two solutions?
If the discriminant is greater than zero (b^2 - 4ac) > 0, then the equation have two roots that are real and unequal. Further, the roots are rational if and only if (b^2 - 4ac) is a perfect square, otherwise the roots are irrational.Example:Find the equation whose roots are x = u/v and x = v/uSolution:x = u/vx - u/v = 0x = v/ux - v/u = 0Therefore:(x - u/v)(x - v/u) = (0)(0) or(x - u/v)(x - v/u) = 0Let c = u/v and d = v/u. We can write this equation in equation in the form of:(x - c)(x - d) = 0x^2 - cx - dx + CD = 0 orx^2 - (c +d)x + CD = 0The sum of the roots is:c + d = u/v + v/u = (u)(u)/(v)(u) + (v)(v)/(u)(v) = u^2/uv + v^2/uv = (u^2 + v^2)/uvThe product of the roots is:(c)(d) = (u/v)(v/u) = uv/vu = uv/uv = 1Substitute the sum and the product of the roots into the formula, and we'll have:x^2 - (c +d)x + CD = 0x^2 - [(u^2 + v^2)/uv]x + 1 = 0 Multiply both sides of the equation by uv(uv)[x^2 - ((u^2 + v^2)/uv))x + 1] = (uv)(0)(uv)x^2 - (u^2 + v^2)x + uv = 0 which is the equatiopn whose roots are u/v, v/u
What is integration by parts formula?
uv - integral of (v * du)
Can UV Rays be reflected by a mirror?
Purely from observation of devices utilising UV rays i'd go with yes, as there are personal solar chargers that include mirrored reflectors to increase charge efficiencies.
What is lambda max of S-adenosyl-methionine in uv spectrum?
254 nm
What is the reported UV lambda max of Vildagliptin drug?
The reported UV lambda max of Vildagliptin drug is 254 nm.
What bacteria does 254 nm and 185 nm uv kill?
bacteria and viruses and microorganisms. I think 185nm kills some organic stuff.
What difference between pda and uv detector in hplc?
PDA - Photo diode array UV- Ultra violet with use of PDA detector, we can measure the area or height of particular peak at different wavelengths ranging from 200 to 800 nm by injecting the solution at once. Where as in uv detector we can measure the area or height of the peak only at two different wavelengths. But that wavelengths also to be selected before injecting the solution.
What is Difference Between HPLC UV detector Spectrophotometer uv detector?
hi, could any one answer what is the difference between hplc uv detector and spectrophotometer uv detector ? my id is debendra_mallick2002@yahoomail.com
What is difference between an HPLC UV detector and a fluorescence detector?
flourescence is more sensetive than UV detection
What is the function of detector in UV spectrophotometer?
Detector converts optical signal to electric signal
What is the working temperature of mercury lamp?
The peaks of the emission from the ionized vaporof mercury are:-- 184.5 nm . . . UV-C-- 253.7 nm . . . UV-C-- 365.4 nm . . . UV-A-- 404.7 nm . . . violet-- 435.8 nm . . . blue-- 546.1 nm . . . green-- 578.2 nm . . . yellow-orange.The quantum wavelength of the lamp itself is much shorter than any of those.
What is different between pda detecto and uv detector?
technical difference is flow cell is placed in between lamp and optics but in uv it is placed after grating. and flow cell receives monochromatic light in uv detector but polychromatic in pda.
Is a blacklight uv light?
Yes it is, it is UV-A and in the range 400 nm-315 nm but the best Wavelength for showing colours and making your teeth glow is 365nm.
What is the wavelenght of uv rays?
Less than that of visible light, which is in the range of about 350-700 nm - so UV rays would have a wavelength below 350 nm.
Is the deep UV extreme uv lithography are the same?
No. Deep UV refers to 193 - 245 nm UV radiation which can be easily controlled using conventional optics and created by conventional lasers. Extreme UV refers to shorter wavelength UV light (around 13 nm) which comes with a number of engineering challenges related to absorption, requiring the optics to be contained within a vacuum and the use of purely reflective optics to minimize absorption by air and glass, respectively.
