The only situation where it will not add weight is if both of these is true:
In the above case, the weight of the displaced water (the water that overflows) is equal to the weight of the freely floating ball. There is no net gain in weight. If the bucket is not initially full to the brim, or if the ball rests on the brim of the bucket without floating freely, then the ball will add weight.
No, I haven't. But, when the bucket is in the water, the weight is supported by the water in the well. Once the bucket is raised out of the water, the weight is no longer supported, and the full weight of the bucket and the water within the bucket is felt as it is raised towards the surface.
It depends on the bucket size, but usually a standard size bucket would hold a few litters of water.
A gallon of water weighs about 8.34 pounds. If you have a good sized bucket with a gallon of water in it and you put a 5-pound fish in the bucket, you'll have a bucket that weighs about 13.34 pounds (plus the weight of the bucket). That's as long as the bucket doesn't overflow. The fish will (usually) be neutrally bouyant in the water, and it will be essentially weightless in that water. But its weight will add to that of the water in the bucket. No, it won't weigh 15 pounds, but it will weigh in as suggested. However, the weight of the water itself will not change.
to counterbalance the weight of the water bucket and make for easier lifting
8 kg is the weight of the bucket plus a full bucket of water. 4.8 kg is the weight of the bucket plus half a bucket of water.8 = b + w4.8 = b + w/2Subtract #2 from #1 to get3.2 = w/2so6.4 = wsubstitute that into #1 to get 1.6 kg for the bucket.The question is what is the weight with w/41.6 kg for the bucket and (4.8)/4 for the water1.6 + 1.2 = 2.8 kg ■
If the bucket is empty, and sealed so that no water can get in it, then it takes 41.8 pounds (minus the empty weight of the bucket) to completely submerge it.
pounds
Bucket plus Water = B + W = 50 kg Bucket + 0.5*Water = B + W/2 = 30 kg Subtracting the second equation from the first gives W/2 = 20 kg So W = 40 kg Then B + W = 50 kg gives B = 10 kg.
Pick up the weight. Fill the bucket with water. Put the bucket on one chain and the weight on another. Tilt your device toward you so the door falls down over the water like a drawbridge.See related link for screenshots.Click the bucket and fill it with water and put it on a chain. There's a weight at the bottom left, click it and put it on the other weight. Shake your device and the door will fall :) YOUR ALMOST DONE!! :D
Did you mean "shadoof", a bucket on a pole with a counter weight used to lift water.
83.4 lbs - excluding the weight of the bucket !