675 = 3 x 3 x 3 x 5 x 5 or 33 x 52
No prime numbers can be equal to 33, as 33 is not a prime number. It is divisible by 3. Prime numbers are only divisible by 1 and themselves, and 33 does not meet this criterion.
23 x 33 = 216
Any two prime numbers, eg 3 and 17 also any two co-prime numbers eg 26 and 33
As a product of its prime factors: 3 times 11 = 33
33 = 3 x 11
2 x 33 x 52
As a product of its prime factors expressed in exponents it is: 23*33 = 216
675 = 3 x 3 x 3 x 5 x 5 or 33 x 52
No prime numbers can be equal to 33, as 33 is not a prime number. It is divisible by 3. Prime numbers are only divisible by 1 and themselves, and 33 does not meet this criterion.
Not all the time, 11 x 3 = 33
23 x 33 = 216
There are no prime numbers between 33 and 36.
To find the HCF of 3 numbers you first need to write them as the product of their prime factors. In this case you get: 11 = 11 33 = 3x11 121 = 11x11 The next step is to identify any common prime factors. In this case, all three numbers have an 11 as a prime factor. Therefore, the HCF of 11, 33 and 121 is 11.
27 = 3 x 3 x 3 = 33
there are 3 prime numbers in between 21 and 33... they are 23,29, 31.
Any two prime numbers, eg 3 and 17 also any two co-prime numbers eg 26 and 33