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Solution:

CLR C ;make CY=0

MOV A, #0E7H ;load the low byte now A=E7H

ADD A, #8DH ;add the low byte

MOV R6, A ;save the low byte sum in R6

MOV A, #3CH ;load the high byte

ADDC A, #3BH ;add with the carry

MOV R7, A ;save the high byte sum

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11y ago
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11y ago

LDA 4200h

cma

adi, 01h

STA 4300hhlt

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13y ago

LXI H.2500

LXI D 2601

MOV B,M

*CALL 2300

STAX D

CALL 2400

INX D

DCR B

JNZ*

HLT

Jitendra kumar pandey

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14y ago

mov ax,firstnumber add ax,secondnumber mov result,ax

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11y ago

kuldeep-great.blogspot.com

check this out you find your answer ...

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Q: Write 8085 assembly language program to find the 2's complement of a given 8 bit integer?
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