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Write a c plus plus program that counts the no. of 1 bit in a given integer?
Wiki User
∙ 14y ago
int bitcount (unsigned n)
{
int bitc= 0;
while (n) {
++bitc;
n = n&(n-1);
}
return bitc;
}
Wiki User
∙ 14y ago
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As given it is an integer. However, if redrafted as 0.634920634920634... at every Which is a recurring decimal to infinity. This decimal recurs at every sixth digit. So we say Let P = 0.634920634920634... 1000000P = 634920.634920634... Subtract 999999P = 634920 . 0 Note the decimals subtract to zero. P = 634920/999999 Cancel down by '3' 211640/333333 The answer!!!!! Subtract
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