write a shell program for finding out gcd of three given numbers? write a shell program for finding out gcd of three given numbers? write a shell program for finding out gcd of three given numbers? check bellow link http://bashscript.blogspot.com/2009/08/gcd-of-more-than-two-numbers.html
The mean times three will be the total of all three numbers. Multiply the mean times three and subtract the sum of the two numbers from that total.
You add the three numbers, then divide the result by 3.
Of the three numbers given, the largest is 3.274.
2 is the least of the three given numbers.
It is not possible to answer the question because the three numbers are not given. Moreover, this browser will not support the necessary graphics.
The LCM of the given three numbers is 48
The given three numbers are all prime numbers
Their given! You found it! Boom
The LCM of the given three numbers is 168
The mean times three will be the total of all three numbers. Multiply the mean times three and subtract the sum of the two numbers from that total.
You add the three numbers, then divide the result by 3.
Pythagorean triple
When you put the numbers in numerical order, it is the middle number. For example: you are given these three numbers- 9,3,5 put in numerical order: 3,5,9 median is 5.
echo Enter 3 numbers with spaces in between read a b c l=$a if [ $b -gt $l ] then l=$b fi if [ $c -gt $l ] then l=$c fi echo Lagest of $a $b $c is $l
6 is the mean of the three numbers given.
The LCM of the given three numbers is 105
The gcf of the given three numbers is 1