Write a c program to compute the average of 3 input quizzes then display the result?

Answer 1

#include <stdio.h>

#include<iostream.h>

#include<conio.h>

#include<windows.h>

int main()

{

int q1, q2, q3, ave;

printf ("Enter 1st quiz: ");

scanf ("%d", &q1);

printf ("Enter 2nd quiz: ");

scanf ("%d", &q2);

printf ("Enter 3rd quiz: ");

scanf ("%d", &q3);

ave=(q1+q2+q3/3);

printf ("Average quiz is %d", ave);

getch() ;

}

Answer 2

Given the three numbers you would need to:

Count the frequency of the numbers so that you can then give the mode average;

Followed by sorting them into order so that you can give the median average;

And adding them and dividing by 3 to give the mean average - for this last one I would recommend that you use float (or double) to store and process your numbers and print to a reasonable number of decimal places, unless you are intending to display the results using rationals, in which case structures using ints may be useful.

As you can see, from this last average calculation, you will need to define your input range for the numbers as there is limited storage in an int.

Answer 3

The specific code will depends upon the inputs from the quizzes. Also, are you to calculate the score of each quiz, or averages of other factors?

Once you have that decided, calculating the average of any number of input values is basic arithmetic. Add all of the values together, and divide by the number of values.

So if you had three quizzes and had to calculate the average score of all three quizzes, the expression would be:

(score1+score2+score3)/3

Keep in mind that if you want floating point precision (i.e. decimal points), a float or (unlikely) a double would be your best choice in type. Otherwise, a regular integer type would do nicely: if your scores are 100% or lower, for instance, a char type (signed or unsigned doesn't matter) would do nicely.