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Write a fortran code to calculate the root of quadratic equation?
Wiki User
∙ 11y ago
implicit double precision(a-h,o-z)
write(*,*) "please provide the a,b,c coeff"
read(*,*) A,B,C
D=B*B-4*A*C
if(D.GT.0) then
root1=(-B/(2*A))+(SQRT(D))/(2*A)
root2=(-B/(2*A))-(SQRT(D))/(2*A)
write(*,*) root1,root2
elseif(D.EQ.0) then
root1=(-B/(2*A))
root2=root1
write(*,*) root1,root2
else
root1=(-B/(2*A))+(SQRT(-D))/(2*A)
root2=(-B/(2*A))-(SQRT(-D))/(2*A)
a=(root1+root2)/2
b=(root1-root2)/2
write(*,*) 'realpartroot=',a, 'complexpartroot=',b
endif
stop
END
Wiki User
∙ 11y ago
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How do you write a quadratic equation in standard form?
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When the roots are equal of a quadratic equation?
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