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Q: Write a number between 200 and 300 that is divisible by 2 3 and 5?

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There are 33 numbers between 200 and 300 that are divisible by three.

There are 5 multiples of 18 between 200 and 300. (An even number divisible by 9 is any number divisible by 18).

22,200 is a number that can be divisible by 111 and 200.

The number is 115.

201

201

201 is one such.

235

201 is one such number.

The probability is 67/200.

150

213.

231 and 285

333

My answer is 201

How about: 270

210

These numbers between 200 and 300 are divisible by nine but not by two: 207, 225, 243, 261, 279, 297.

270.

public class TestMain { /** * @param args */ public static final void main(String[] args) { int sum = 0; int count = 0; for (int i = 100; i <= 200; i++){ if(i%7 == 0){ count++; sum = sum + i; System.out.println("The number is: " + i); } } System.out.println("Number of values divisible by 7 between 100 and 200 is: " + count); System.out.println("Sum of values divisible by 7 between 100 and 200 is: " + sum); } } Output: The number is: 105 The number is: 112 The number is: 119 The number is: 126 The number is: 133 The number is: 140 The number is: 147 The number is: 154 The number is: 161 The number is: 168 The number is: 175 The number is: 182 The number is: 189 The number is: 196 Number of values divisible by 7 between 100 and 200 is: 14 Sum of values divisible by 7 between 100 and 200 is: 2107

divisible by 2 means even number. so it can not be even number. divisible by 3 means add all the number and divide 3..number 99 is divisible by 3 we start 99+3=102 but it is even number..105,108,111,114,117,120. (108,114,120 are even number so they can not be answer) answers are 105, 111,117.

How about 240 or 270

210

There are 22 such numbers.