To find a number between 200 and 300 that is divisible by 5, we need to look for multiples of 5 within that range. The first multiple of 5 after 200 is 205, and the last multiple before 300 is 295. Therefore, the number between 200 and 300 that is divisible by 5 is 205.
The number is 115.
i believe the correct answer is 219
To find the total number of integers between 100 and 300 that are divisible by 3, we first determine the smallest and largest integers in this range that are divisible by 3. The smallest integer divisible by 3 is 102, and the largest is 297. To find the total number of integers between 102 and 297 that are divisible by 3, we calculate (297-102)/3 + 1, which equals 66. Therefore, there are 66 integers between 100 and 300 that are divisible by 3.
150 ÷ 9 = 16 r 6 → the first natural number between 150 and 300 divisible by 9 is 9 × 17 (=154)300 ÷ 9 = 33 r 3 → the last natural number between 150 and 300 divisible by 9 is 9 × 33 (=297)→ there are 33 - 17 + 1 = 17 natural numbers between 150 and 300 divisible by 9.
There are 5 multiples of 18 between 200 and 300. (An even number divisible by 9 is any number divisible by 18).
To find a number between 200 and 300 that is divisible by 5, we need to look for multiples of 5 within that range. The first multiple of 5 after 200 is 205, and the last multiple before 300 is 295. Therefore, the number between 200 and 300 that is divisible by 5 is 205.
The number is 115.
201 is one such.
These numbers between 200 and 300 are divisible by nine but not by two: 207, 225, 243, 261, 279, 297.
201 is one such number.
213.
210
How about: 270
My answer is 201
270.
210