Write a program in C to accept 10 values in an integer array and show odd even and negative numbers?

Answer 1

#include<stdio.h>

#include<conio.h>

void main()

{

int a[10],count_even=0,count_odd=0,neg=0,i;

printf(" Enter the value in Array \n");

for(i=0;i<10;i++)

scanf("%d", &a[i]);

/* Calculating number of odd and even integer's */

for(i=0;i<10;i++)

{

if((a[i]%2 ==0))

count_even++;

if((a[i]%2==1))

count_odd++;

if(a[i]<0)

neg++;

}

/* display the number of odd and even integer's */

printf(" Total number of even integer are %d\n ",count_even);

printf("Total number of odd integer are %d\n", count_odd);

printf(" Total negative integer are %d", neg);

getch();

}

Answer 2

#include

#include

int main()

{

int i ,even=0,odd=0;

int a[10];

printf("enter numbers \n");

for(i=0;i

Answer 3

dtuke