#include <stdio.h>
int main(int argc, char **argv)
{
if (argc<1) {
printf("Usage: %s number\n",argv[0]);
return -1;
}
int digits=1, i=atoi(argv[1]);
while (i/=10) ++digits;
printf("%d\n",digits);
}
no thanks
One way to do this is to convert the number to a String, then use the corresponding String method to find out the length of the String.
5
There are many shell programs that will find the sum of the square of individual digits of a number. A small example is: SD=3n=2, sum=2, and SD=2.
k
class Sum_Of_Digits { public static void printSumandnoofdigits(int n) { int temp = n; int count = 0; int sum = 0; while ( n > 0 ) { sum = sum + n % 10; n = n / 10; count ++; } System.out.println("The number is..." + temp ); System.out.println("The sum of digits is..." + sum); System.out.println("The number of digits is..." + count); } }
You can use the Math.sqrt() method.
Shell problems are programs that can be run to find out information about numbers. The problem can help find an even or odd number, or what the sum of a cube is.
Yes, do write, or if you're too lazy to your homework, use google.
Write your own prime number program and find out.
Add the digits together. The sum of the digits of 23 is 5.
45