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Write a shell script to print given number in reverse order in Unix?
Wiki User
∙ 15y ago
# Algo:
# 1) Input number n
# 2) Set rev=0, sd=0
# 3) Find single digit in sd as n % 10 it will give (left most digit)
# 4) Construct revrse no as rev * 10 + sd
# 5) Decrment n by 1
# 6) Is n is greater than zero, if yes goto step 3, otherwise next step
# 7) Print rev
#
if [ $# -ne 1 ]
then
echo "Usage: $0 number"
echo " I will find reverse of given number"
echo " For eg. $0 123, I will print 321"
exit 1
fi
n=$1
rev=0
sd=0
while [ $n -gt 0 ]
do
sd=`expr $n % 10`
rev=`expr $rev \* 10 + $sd`
n=`expr $n / 10`
done
echo "Reverse number is $rev"
Wiki User
∙ 15y ago
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