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The general equation for a straight line is: y=mx+c

m being the gradient (slope), and c being the y intercept (which isn't important in this question)

So firstly, we substitute the slope into the rule which gives us:

y=2x+c

Then we substitute in the point (4,1), 4 being the x-value and 1 being the y-value. This means that when x=4, y=1, so if we put this into our equation:

(4,1) => 1=2x4+c

1=8+c

Now subtract 8 from both sides

-7 = c

Finally, substitute your m and c into the rule and you get your straight line equation:

y=2x-7

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Q: Write an equation of the line that passes through the point 4 comma 1 and has a slope of 2?
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What would the equation of a line be if it went through the point 2 comma 2 and its yintercept was 10?

We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).Using these two points, we can find the slope of the line,m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which isy = -4x + 10.


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Equation of a line through point (x0, y0) with gradient m is given by: y - y0 = m(x - x0) the gradient m between two points (x0, y0) and (x1, y1) is given by: m = change_in_y/change_in_x = (y1 - y0)/(x1 - x0) → equation of line through (9, 0) and (5, 3) is: y - 0 = ((3 - 0)/5 - 9)) (x - 9) → y = (3/-4) (x - 9) → 4y = -3x + 27 → equation of line through (0, 0) and (0.5, 3) is: y - 0 = ((3 - 0)/(0.5 - 0)) (x - 0) → y = (3/0.5)x → y = 6x This gives two simultaneous equations which when solved give the point where the two lines intersect: y = 6x → 4y = 24x → 24x = -3x + 27 → 27x = 27 → x = 1 → y = 6 × 1 = 1 → point of intersection is (1, 6)


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Not usually : "Thank you for listening to me" does not need a comma. However, if you write their name afterward ("Thanks, Fred."), you need a comma after thank you.


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