We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).
Using these two points, we can find the slope of the line,
m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.
Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which is
y = -4x + 10.
If you mean a slope of -12 through the point (5, 3) the equation is y = -12x+63
If you mean a slope of -10 through the point (1, 4) then the equation is y = -10x+14
Assuming the point is (9, -4), the equation is y = -4.
If you mean: slope of -13 and point of (5, 7) then the equation is y = -13x+72
If you mean slope of -10 and point of (1, 4) then the equation is y = -10x+14
The equation of a vertical line passing through the point (a, b) is x a.
If you mean a slope of -12 through the point (5, 3) the equation is y = -12x+63
If you mean a slope of -10 through the point (1, 4) then the equation is y = -10x+14
The point with the given coordinates does not lie on the curve and so the question makes no sense.
The equation of a horizontal line is of the form y=k, where k is the y-coordinate of the point through which the line passes. Therefore, the equation of the horizontal line through the point (8, -10) is y = -10.
sda
You can have infinitely many lines through one specific point, each with a different equation. If you want to have a general equation for ANY line that goes through that point, use the point-slope equation for a line, and use a variable for the slope.
Assuming the point is (9, -4), the equation is y = -4.
That will depend on the value of the slope which has not been given.
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The equation is [ y = 3 ].
Point: (2, 17)Slope: 7Equation: y = 2x+13