We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).
Using these two points, we can find the slope of the line,
m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.
Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which is
y = -4x + 10.
If you mean a slope of -10 through the point (1, 4) then the equation is y = -10x+14
If you mean a slope of -12 through the point (5, 3) the equation is y = -12x+63
Assuming the point is (9, -4), the equation is y = -4.
If you mean slope of -10 and point of (1, 4) then the equation is y = -10x+14
If you mean: slope of -13 and point of (5, 7) then the equation is y = -13x+72
If you mean a slope of -10 through the point (1, 4) then the equation is y = -10x+14
If you mean a slope of -12 through the point (5, 3) the equation is y = -12x+63
The equation of a horizontal line is of the form y=k, where k is the y-coordinate of the point through which the line passes. Therefore, the equation of the horizontal line through the point (8, -10) is y = -10.
You can have infinitely many lines through one specific point, each with a different equation. If you want to have a general equation for ANY line that goes through that point, use the point-slope equation for a line, and use a variable for the slope.
sda
The point with the given coordinates does not lie on the curve and so the question makes no sense.
Assuming the point is (9, -4), the equation is y = -4.
That will depend on the value of the slope which has not been given.
The equation is [ y = 3 ].
write an equation that has a slope 7 and passes through the point (2,17)
Equation of a line through point (x0, y0) with gradient m is given by: y - y0 = m(x - x0) the gradient m between two points (x0, y0) and (x1, y1) is given by: m = change_in_y/change_in_x = (y1 - y0)/(x1 - x0) → equation of line through (9, 0) and (5, 3) is: y - 0 = ((3 - 0)/5 - 9)) (x - 9) → y = (3/-4) (x - 9) → 4y = -3x + 27 → equation of line through (0, 0) and (0.5, 3) is: y - 0 = ((3 - 0)/(0.5 - 0)) (x - 0) → y = (3/0.5)x → y = 6x This gives two simultaneous equations which when solved give the point where the two lines intersect: y = 6x → 4y = 24x → 24x = -3x + 27 → 27x = 27 → x = 1 → y = 6 × 1 = 1 → point of intersection is (1, 6)
If you mean a slope of 6 passing through the point of (1, 3) then the equation works out as: y = 6x-3