We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).
Using these two points, we can find the slope of the line,
m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.
Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which is
y = -4x + 10.
If you mean a slope of -10 through the point (1, 4) then the equation is y = -10x+14
If you mean a slope of -12 through the point (5, 3) the equation is y = -12x+63
Assuming the point is (9, -4), the equation is y = -4.
If you mean slope of -10 and point of (1, 4) then the equation is y = -10x+14
If you mean: slope of -13 and point of (5, 7) then the equation is y = -13x+72
If you mean a slope of -10 through the point (1, 4) then the equation is y = -10x+14
If you mean a slope of -12 through the point (5, 3) the equation is y = -12x+63
The equation of a horizontal line is of the form y=k, where k is the y-coordinate of the point through which the line passes. Therefore, the equation of the horizontal line through the point (8, -10) is y = -10.
The point with the given coordinates does not lie on the curve and so the question makes no sense.
You can have infinitely many lines through one specific point, each with a different equation. If you want to have a general equation for ANY line that goes through that point, use the point-slope equation for a line, and use a variable for the slope.
sda
Assuming the point is (9, -4), the equation is y = -4.
That will depend on the value of the slope which has not been given.
The equation is [ y = 3 ].
write an equation that has a slope 7 and passes through the point (2,17)
The decimal point. But note that in many countries it is a comma, not a dot.The decimal point. But note that in many countries it is a comma, not a dot.The decimal point. But note that in many countries it is a comma, not a dot.The decimal point. But note that in many countries it is a comma, not a dot.
Equation of a line through point (x0, y0) with gradient m is given by: y - y0 = m(x - x0) the gradient m between two points (x0, y0) and (x1, y1) is given by: m = change_in_y/change_in_x = (y1 - y0)/(x1 - x0) → equation of line through (9, 0) and (5, 3) is: y - 0 = ((3 - 0)/5 - 9)) (x - 9) → y = (3/-4) (x - 9) → 4y = -3x + 27 → equation of line through (0, 0) and (0.5, 3) is: y - 0 = ((3 - 0)/(0.5 - 0)) (x - 0) → y = (3/0.5)x → y = 6x This gives two simultaneous equations which when solved give the point where the two lines intersect: y = 6x → 4y = 24x → 24x = -3x + 27 → 27x = 27 → x = 1 → y = 6 × 1 = 1 → point of intersection is (1, 6)