Just write a loop that goes through "candidates" (for example, numbers from 2 to 100). To check whether each number is a Prime number, write a second loop that checks whether it is divisible by all numbers from 2 up to the number itself. If the first factor you thus find is the number itself, then it is a prime number. For example, in Java:
...
for (i=2; i<=100; i++)
Â? for (j=2; j<= i; i%j<>0);
Â? if (i==j) System.out.println(i);
...
Note that the second "for" loop uses an empty instruction, so it will just increment the variable "j" until it finds a factor.
Also note that the program is "optimized" for simplicity; it is not optimized for speed.
A number as a product of prime numbers would be "x".
Numbers divisible by 1 & number itself are called prime numbers. These numbers also have the property to be odd numbers.
You can't write that as the sum of two prime numbers. Note: Goldbach's Conjecture (for expressing numbers as the sum of two prime numbers) applies to EVEN numbers.
That's called the prime factorization.
Prime factorization of 27 = 3x3x3
2x2x2x3
2x2x3x5
2x2x3x3x3
In the same way as you would write any integer.
fdsgfhgdfhgdf
Since there is an infinite set of prime numbers the answer would be infinity.
2x2x2x2x3x3=144