For any number n you could use
* (n % 2 == 0), which would be true for an even number, false for odd For an integer i, a simpler method would be
* (i & 1), which would be true for an odd number, false for even
for(int i = 1; i < 100; i+=2) { System.out.println(i); }
No, thanks.
int main () { int x; printf ("Enter the value of x\n"); scanf ("%d",&x); if (0 == x%2) printf ("Number is even\n") else printf ("Number is odd\n"); }
The pseudo code would be as follows (you figure out the syntax) 1) Prompt the user to enter a number 2) If entered number is alpha, quit program after displaying message that the user ended the program. 3) Otherwise, find Modulo 2 of the entered number. This is a fancy way of saying "find the remainder when the number is divided by 2) 4) If Modulo 2 is zero, the number is even, otherwise odd 5) Display message showing if the entered number was Even or Odd 6) Branch back to step 1
You write odd or even in brackets, but most people should know if it's odd or even as odd numbers end in 1, 3, 5, 7 or 9 and even numbers end in 2, 4, 6,8 or 0.
To write a C program to determine if something is odd or even you need to be a programmer. To write a program in C is complicate and only done by programmers.
for(int i = 1; i < 100; i+=2) { System.out.println(i); }
if n MOD 2 == 0 THEN Write ("Even");
No, thanks.
int main () { int x; printf ("Enter the value of x\n"); scanf ("%d",&x); if (0 == x%2) printf ("Number is even\n") else printf ("Number is odd\n"); }
If the number is odd, that's the answer. If the number is even, write down all the factors and choose the largest one that is odd.
printf ("%d is %s\n", n, n%2 ? "odd": "even");
The pseudo code would be as follows (you figure out the syntax) 1) Prompt the user to enter a number 2) If entered number is alpha, quit program after displaying message that the user ended the program. 3) Otherwise, find Modulo 2 of the entered number. This is a fancy way of saying "find the remainder when the number is divided by 2) 4) If Modulo 2 is zero, the number is even, otherwise odd 5) Display message showing if the entered number was Even or Odd 6) Branch back to step 1
write a program in C that prompts the user with the following lines: a) Add two integers c) Compare two integers for the larger t) Test an integers for odd or even q) Quit
printf(\n "ENTER THE NUMBER\t"); scanf{"%d",&a); while(a!=0); { r=a%2; if(r==0) printf("\n\n THE NUMBER IS EVEN \t"); else printf("\n\n THE NUMBER IS ODD \t"); printf ("\n ENTER THE NUMBER \t"); scanf("%d",&a); } getch(); }
for (int i = 2; i < 10; i ++) printf("%d\n", i); You did say even and odd numbers between 1 and 10. That's allnumbers between 1 and 10.
Q.1 Write a program to print first ten odd natural numbers. Q.2 Write a program to input a number. Print their table. Q.3 Write a function to print a factorial value.