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Write a shell program to find given no is even or odd?
The pseudo code would be as follows (you figure out the syntax) 1) Prompt the user to enter a number 2) If entered number is alpha, quit program after displaying message that the user ended the program. 3) Otherwise, find Modulo 2 of the entered number. This is a fancy way of saying "find the remainder when the number is divided by 2) 4) If Modulo 2 is zero, the number is even, otherwise odd 5) Display message showing if the entered number was Even or Odd 6) Branch back to step 1
Program to check whether the entered number is even or odd?
#include<stdio.h> #include<conio.h> void main() { int n; printf("ENTER NO FOR CHECK........ "); scanf("%d", &n); if(n%2==0) printf("Given No is EVEN"); else printf("Given No is ODD"); getch(); }
Write c program to find the given no is even or odd?
int main () { int x; printf ("Enter the value of x\n"); scanf ("%d",&x); if (0 == x%2) printf ("Number is even\n") else printf ("Number is odd\n"); }
How can you tell whether a given number is a multiple of 2?
If it is even
Is 256 divisible by 2?
YES!!!! Any EVEN number is divisible by '2'. NB Even numbers end in 0,2,4,6 & 8. Since the given number ends in '6' then it is an even number.
