To have an odd number of factors, the number must be a square.
The only squares between 80 and 100 ()inclusive) are 81 and 100 but 81 does not have a factor of 5, and 100 has 9 factors.
Thus the problem (as stated) has no solution.
The numbers which have a factor of 5 must end in 0 or 5; the only numbers between 80 and 100 (inclusive) which match this criteria are {80, 85, 90, 95, 100}, which have {10, 4, 12, 4, 9} respectively.
If you meant 3 PROPER factors (ie all the factors excluding the number itself), then 85 and 95 both have 3 proper factors.
The only way for a number to have exactly 3 factors is to take the square of a prime. In this case, the problem has no solution.
31, 37, 41, 43, 47Pick three.
93000000 is, itself a whole number so you would write it exactly as in the question.
In exactly the same way as it appears at the end of your own question!
Prime factorization is the finding which prime number multiply to get to make the original number. Factors of 75: 1, 3, 5, 15, 25, 75 Prime factors: 3, 5 3 x 5 x 5 = 75
3 x 13 = 39
31, 37, 41, 43, 47Pick three.
You would write it exactly as in the question: 9000You would write it exactly as in the question: 9000You would write it exactly as in the question: 9000You would write it exactly as in the question: 9000
Exactly as it is: 486.4949
3, 5 and 7
If you write every number once, then you will write the number nine exactly once. If you mean "... the digit9, it should appear 20 times: 10 times in the ten's place, and 10 times in the one's place.
write the number 14as a product of prime factor?
Exactly as in the question!
1
Exactly as in the question.
Exactly as in the question.
Exactly as in the question.
93000000 is, itself a whole number so you would write it exactly as in the question.