To have an odd number of factors, the number must be a square.
The only squares between 80 and 100 ()inclusive) are 81 and 100 but 81 does not have a factor of 5, and 100 has 9 factors.
Thus the problem (as stated) has no solution.
The numbers which have a factor of 5 must end in 0 or 5; the only numbers between 80 and 100 (inclusive) which match this criteria are {80, 85, 90, 95, 100}, which have {10, 4, 12, 4, 9} respectively.
If you meant 3 PROPER factors (ie all the factors excluding the number itself), then 85 and 95 both have 3 proper factors.
The only way for a number to have exactly 3 factors is to take the square of a prime. In this case, the problem has no solution.
31, 37, 41, 43, 47Pick three.
93000000 is, itself a whole number so you would write it exactly as in the question.
In exactly the same way as it appears at the end of your own question!
3 x 13 = 39
Prime factorization is the finding which prime number multiply to get to make the original number. Factors of 75: 1, 3, 5, 15, 25, 75 Prime factors: 3, 5 3 x 5 x 5 = 75
31, 37, 41, 43, 47Pick three.
You would write it exactly as in the question: 9000You would write it exactly as in the question: 9000You would write it exactly as in the question: 9000You would write it exactly as in the question: 9000
Exactly as it is: 486.4949
3, 5 and 7
If you write every number once, then you will write the number nine exactly once. If you mean "... the digit9, it should appear 20 times: 10 times in the ten's place, and 10 times in the one's place.
write the number 14as a product of prime factor?
Exactly as in the question!
1
Exactly as in the question.
Exactly as in the question.
Exactly as in the question.
93000000 is, itself a whole number so you would write it exactly as in the question.