To have an odd number of factors, the number must be a square.
The only squares between 80 and 100 ()inclusive) are 81 and 100 but 81 does not have a factor of 5, and 100 has 9 factors.
Thus the problem (as stated) has no solution.
The numbers which have a factor of 5 must end in 0 or 5; the only numbers between 80 and 100 (inclusive) which match this criteria are {80, 85, 90, 95, 100}, which have {10, 4, 12, 4, 9} respectively.
If you meant 3 PROPER factors (ie all the factors excluding the number itself), then 85 and 95 both have 3 proper factors.
31, 37, 41, 43, 47Pick three.
93000000 is, itself a whole number so you would write it exactly as in the question.
The number between 99 and 101 is 100. This number falls exactly in the middle of the two given numbers on the number line. It is the average of 99 and 101, making it the most logical choice for the number between them.
There are an infinite number of decimal numbers between 0.10 and 0.11 .Just write "0.10" and then any digits you want after that (except all zeros),and you'll have a number that's between 0.10 and 0.11 .If you're looking for the one and only number that's exactly half-way betweenthem, then the name of that is the "average" of 0.10 and 0.11 . It's exactly equalto 1/2 of their sum.1/2 (0.10 + 0.11) = 0.15
Between which 2 hundreds is each number? 713?
31, 37, 41, 43, 47Pick three.
You would write it exactly as in the question: 9000You would write it exactly as in the question: 9000You would write it exactly as in the question: 9000You would write it exactly as in the question: 9000
Exactly as it is: 486.4949
If you write every number once, then you will write the number nine exactly once. If you mean "... the digit9, it should appear 20 times: 10 times in the ten's place, and 10 times in the one's place.
3, 5 and 7
Exactly as in the question.
Exactly as in the question.
Exactly as in the question.
Exactly as in the question!
1
93000000 is, itself a whole number so you would write it exactly as in the question.
1000 is a number.