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Comparison of Big-M method and two phase methods in solving linear programming problem?
use two phase method s.t x1+x2+x3>=3 -x1+2x2>=2 -x1+5x2+x3<=4 x1,x2,x3>=0
How many times in a twelve hour period does the sum of the digits on a digital clock equal six and prove it?
notation: natural numbers = 0,1, 2, 3, 4, 5, ....., (some define it without the zero, though) <= means smaller than or equal to, {} is set notation and means a set of numbers : (such that) then some condition. For example {x: x is not a duck} is the set of all things not a duck. Our goal is to prove that there are 21 different times. let x1 = hours, x2 = tens of minutes, x3 = minutes. We are going to prove the statement about the set {x1, x2,x3: 1<=x1 <= 12, 0<= x2<=5, 0<=x3 <= 59, x1 + x2 + x3 = 6}. It will be taken by assumption that this set is the set of digital clock combinations that add up to 6. So then, we must prove that there are unique 21 elements in the set {x1 + x2 + x3 : 1<= x1 <= 12, 0<= x2<=5, 0<=x3 <= 59, x1 + x2 + x3 = 6}. {x1 , x2 , x3 : 1<= x1 <= 12, 0<= x2<=5, 0<=x3 <= 59, x1 + x2 + x3 = 6} = {x1 , x2 , x3 : 1<= x1 <= 6, 0<= x2<=5, 0<=x3 <= 5, x1 + x2 + x3 = 6} because x3<=6, and because if x1 >=1, then x2 + x3 <=5, and x3, x2 >= 0 , so surely x3, x2 <= x5. Either x1 = 1, 2, 3, 4, 5, or 6. Next, x1 + x2 + x3 = 6, so x2 + x3 = 6 - x1. There are n+1 natural numbers between 0 and n (I'm being lazy and not proving this, but the proof would be so much longer if I proved it), and since 0 <= x2 <= 5 <= 6-x1, there are at most 6-x1+1 values of x2 for each value of x1. When x1 = 1, there are a maximum of 6, when x1 = 2, there are 6-2+1 = 5, when x1 = 3, there are 6-3+1 = 4, when x1 = 3, there are 3, then 2, and then 1. Summing this up gives us a maximum of 21. So it is at most 21 and at least 21, so exactly 21.
How do you compute quadratic equation using java?
What do you mean by "compute"? Do you want to graph it? Factor it? Calculate it's function given a set of points that lie on it? If you're looking to compute the function given three points that fall on the parabola, then I have just the code for you. If you're given three points, (x1, y1), (x2, y2) and (x3, y3), then you can compute the coefficients of your quadratic equation like this: a = (y1 * (x2 - x3) + y2 * (x3 - x1) + y3 * (x1 - x2)) / (x1 * x1 * (x2 - x3) + x2 * x2 * (x3 - x1) + x3 * x3 * (x1 - x2)) b = (y1 - y2) / (x1 - x2) - a * (x1 + x2); c = y1 - (x1 * x1) * a - x1 * b; You now can calculate the y co-ordinate of any point given it's x co-ordinate by saying: y = a * x * x + b * x + c;
What do you mean by linearity in parameter and linearity in model?
Any model can be linear/nonlinear. Linearity can be in parameters or in variables. In Y=a+ b*x1 + c*x2 + d*x3 the model is linear in both parameters (b,c,d) and variables(x1,x2,x3) In Y=a+ (b+c)x1 + c*x2 + d*x3 the model is nonlinear in parameters (b,c,d) and linear in variables(x1,x2,x3) In Y=a+ bx1 + c*x2*x3 + d*x3 the model is linear in parameters (b,c,d) and nonlinear in variables(x1,x2,x3) In Y=a+ bx1 + c*x2*x3 + exp(b+d)*x3 the model is nonlinear in parameters (b,c,d) and nonlinear in variables(x1,x2,x3)
Can some one please rate my alien deck?
this is my alien deck so plz try and rate it: monsters 20: alien telepath x2 alien grey x3 alien shocktrooper x2 alien warrior x1 alien skull x3 alien infiltrator x1 cosmic horror gangi'el x2 alien mother x2 alien hunter x3 flying saucer muusik'i x1 spell cards 11: brain control x1 premature burial x1 otherworld - the "A" zone x1 corruption cell "A" x3 reload x1 nobalman of crossout x1 "A" cel breeding device x1 creature swap x1 mistical space typhoon x1 traps 9: orbital bombardment x1 brain washing beam x3 crop circles x1 trap hole x1 mass hypnosis x1 call of the haunted x1 cell explosion virus x1 and thats it so i hope someone can help plz rate it out of 10 thx....
What is the best Yu-Gi-Oh warrior deck with elemental or destiny heroes?
I'd say definitely Eheros! My ehero deck is pretty awesome so this is my recipe: Monsters . Bladedge x2 . Clayman x2 . Avian x3 . Sparkman x3 . Wildheart x3 . Burstinatrix x3 . Woodsman x1 . Heat x1 . Stratos x1 . Wroughtweiler x1 . King of the swamps x2 Fusion monsters . Phoenix enforcer x1 . Shinig flare wingman x1 . Tera Firma x1 . Inferno x1 . Rampart blaster x2 . Wildedge x2 . Shining Phoenix enforcer x1 . Flame wingman x1 . Thunder Giant x1 Spells . O-Oversoul x1 . Mystical sace typhoon x1 . Fusion gate x2 . Skyscraper x1 . Fusion sage x1 . Super polymerization . Polymerization x2 . Future Fusion x1 . R-Righteous Justice x1 . E-Emergency call x3 Traps . Threatening roar x1 . Elemental Recharge x1 . Mirror force x1 . A hero emerges x1 . Magical cylinder x1 . Hero blast x1 . Waboku x1 It works for me and I normally fusion summon on my w1st or 2nd turn. :)
What is in a blackwing deck for Yu-Gi-Oh?
Here is a really good blackwing deck: Monsters 21: x2 blackwing sirrocco the dawn x2 blackwing blizzard the far north x3 blackwing bora the spear x3 blackwing shura the blue flame x1 dark armed dragon x1 blackwing gale the whirlwind x1 plaugespreader zombie x1 blackwing elphin the raven x3 blackwing vayu the emblem of honor x1 the dark creator x3 blackwing kalut the moon shadow SPELLS 10: x2 swallows nest x1 M.S.T x1 heavy storm x2 burial from a different dimension x2 allure of darkness x1 mind control x1 brain control TRAPS 11: x1 mirror force x1 delta crow anti reverse x1 call of the haunted x3 Icarus attack x2 mirror of oaths x1 solemn judgment x2 dark bribe SYNCHROS: x1 stardust dragon x1 red dragon archfiend x1 ancient fairy dragon x1 armory arm x1 black rose dragon x1 thought ruler archfiend x1 magical android x3 blackwing armed wing x3 blackwing armor master x1 brioniac, dragon of the ice barriers x1 ally of justice catoster side deck: WHATEVER YOU WANT AGAINST LIGHTSWORN OR ANY OF THE OTHER MAJOR DECKS! P.S. I am sorry some of this needs to be changed. --- This deck is ok, but here's a better balance: Monsters : 22 X1 Plaguespreader Zombie X1 Dark Armed Dragon X1 Blackwing Gale the Whirlwind X3 Blackwing Kalut the Moon Shadow X3 Blackwing Sirocco The Dawn X3 Blackwing Blizzard the Far North X3 Blackwing Shura the Blue Flame X3 Blackwing Bora The Spear X2 Blackwing Vayu the Emblem of Honor X2 Dark Grepher Spells : 13 X2 Black Whirlwind X2 Book of Moon X1 Mystical Space Typhoon X1 Heavy Storm X1 Brain Control X1 Mind Control X1 My Body as a Shield (some ppl say dark illusion is better but i use this) X1 Against The Wind (better then dark eruption cuss u can get shura and bora back) X1 Lightning Vortex X1 Allure of Darkness X1 Giant Trunade Traps : 9 X3 Icarus Attack X2 Bottomless Trap Hole X2 Dimensional Wall X1 Royal Oppression X1 Solemn Judgment
If you have Arceus or regigigas i will find almost any shiny Pokemon that is not legendary and trade it for one of them?
i have no idea what your talking about (Empoleonking) you mean you want to trade any shiny Pokemon for a Regigigas or a Arceus? (empoleonking) yep as long as its not legendary cuz i relly want arceus and regigigas (filmore85) here are all my shinys psyduck x4, dratini x2, gyarados x4, bronzong x1, seaking x2, machop x1, larvitar x1, geodude x4, skarmory x1, camerupt x3, pelipper x1, golduck x2, shinx x1, staravia x1, shellos (pink) x3, graveler x2, banette x1, snover x2, sneasel x7, bronzor x5, gible x1, raichu x1, bidoof, x2, bibarel x1, rhydon x2, weezing x1, numel x1, machoke x2, magcargo x1, meditite x3, madicham x2, kricketune x2, fearow x1, gastradon(pink) x3, floatzel x2, ditto x3, chingling x1, cleffa x1, nosepass x2, whiscash x4, zubat x2, illumise x1, dugtrio x2, hippopotas x1, unown x3. (filmore85) i also do requests if you have any.my friend code is 0603 8229 6574 (filmore85)
What is the formula for healthy cell on vampire island poptropica?
garlic x3, wolfsbane x3, mandrake root x1
How do you create a quadratic model from a list of data x values 140 150 170 175 205 y values 1.4 1.25 0.93 0.78 0.43 please please please help?
The step-work involved in proving this would be too long and detailed to show here, but the end result is this: We're given three verticies, defined by the points (x1, y1), (x2, y2), and (x3, y3). We want to use them to define a parabola in this format: f(x) = ax2 + bx + c We can find our a, b and c coefficients with the following equations: a = [y1(x2 - x3) + y2(x3 - x1) + y3(x1 - x2)] / [x12(x2 - x3) + x22(x3 - x1) + x32(x1 - x2)] b = (y1 - y2) / (x1 - x2) - a(x1 + x2) c = y1 - a(x12) - b(x1)
Matrix inverse method ------ x1 x2 x33000 -x1 5x2-x30 2x1-3x30?
inverse matrix. x1+x2+x3=3,000 -x1+5x2=0 2x1-3x3=0.
Find number of integer solution of X1 x2 x324?
find number of integer solution of X1+x2+x3=24
