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First, factorise:
x2 + 5x - 6 = (x + 6)(x - 1) = 0; whence, either
x + 6 = 0, or
x - 1 = 0.
The product of two factors equals zero, exactly when one or other of the two factors equals zero.
Thus, the solution must be x = 1 or -6. If x equals either of those two values, then the original equation will be true.
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∙ 13y ago
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X2 plus 5x plus 3 equals 9?
x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1
X2 plus 4x - 9 equals 5x plus 3?
x2 + 4x - 9 = 5x + 3 ∴ x2 - x - 12 = 0 ∴ (x + 3)(x - 4) = 0 ∴ x ∈ {-3, 4}
What are solutions to the equation x2 plus 4x-9 equals 5x plus 3?
x2+4x-9 = 5x+3 x2+4x-5x-9-3 = 0 x2-x-12 = 0 (x+3)(x-4) = 0 x = -3 or x = 4
X2 plus 5x plus 4 equals 0?
-x2 + 5x - 4 = 0. Then, x2 - 5x + 4 = (x - 4)(x - 1) = 0; whence, x = 1 or 4. Checking, -1 + 5 - 4 = 0; and -16 + 20 - 4 = 0.
X2 plus 3x-7 equals 5x plus 8?
x2 + 3x - 7 = 5x + 8; thus, x2 + 3x - 7 - 5x - 8 = x2 - 2x - 15 = (x - 5)(x + 3) = 0. Therefore the solution is x = 5 or -3.
X2 plus 5x plus 3 equals 9?
x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1
X2 plus 4x - 9 equals 5x plus 3?
x2 + 4x - 9 = 5x + 3 ∴ x2 - x - 12 = 0 ∴ (x + 3)(x - 4) = 0 ∴ x ∈ {-3, 4}
What are solutions to the equation x2 plus 4x-9 equals 5x plus 3?
x2+4x-9 = 5x+3 x2+4x-5x-9-3 = 0 x2-x-12 = 0 (x+3)(x-4) = 0 x = -3 or x = 4
X2 plus 5x plus 4 equals 0?
-x2 + 5x - 4 = 0. Then, x2 - 5x + 4 = (x - 4)(x - 1) = 0; whence, x = 1 or 4. Checking, -1 + 5 - 4 = 0; and -16 + 20 - 4 = 0.
X2 plus 3x-7 equals 5x plus 8?
x2 + 3x - 7 = 5x + 8; thus, x2 + 3x - 7 - 5x - 8 = x2 - 2x - 15 = (x - 5)(x + 3) = 0. Therefore the solution is x = 5 or -3.
What number is used to complete the square for the equation x2 plus 5x equals 0?
x = 0 or x =-5
What does x2-5x equals 0?
x2 - 5x = 0x (x - 5) = 0x = 0andx = 5
Factor x2 plus 5x plus 6 equals 0?
You don't factor an equation. You factor an expression.So we'll forget about the "equals 0" for a second, while we factor "x2 plus 5x plus 6".x2 + 5x + 6 = (x + 3) (x + 2).Now, if you want this expression to be equal to zero, that can only happen when 'x' is -2 or -3.
What are the possible values for x if x squared plus 5x equals 6?
x2 + 5x =6 x2+5x -6 = 0 (x+6)(x-1) = 0 x+ 6 = 0 x = -6 x-1 = 0 x = 1
What is x2 plus 5x plus 9 equals 0?
It has no solutions because the discriminant of the quadratic equation is less than zero.
X2 plus 5x -14 equals 0?
(x + 7) + (x - 2) x= -7 or 2
Solutions to the quadratic equation x2 - 5x plus 4 equals 0 are?
x = 1 and x = 4
