x2 + 5x - 120 can not be factored.
x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1
x2+5x-6 = (x+6)(x-1) when factored
x2-5x+4 = (x-1)(x-4) when factored
(x + 8)(x - 3)
x2-5x+4 = (x-1)(x-4) when factord
x2 + 5x - 120 can not be factored.
5(x2 + x + 1)
Since 5x is a factor of both terms, divide it. 5x3 + 5x = 5x(x2 + 1)
x2+5x+6 = (x+2)(x+3)
x(x2+5x+6)
x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1
x2-5x-36 = (x-9(x+4) when factored
x2+5x-6 = (x+6)(x-1) when factored
x2-5x+4 = (x-1)(x-4) when factored
x - 3
(x + 8)(x - 3)