You don't factor an equation. You factor an expression.
So we'll forget about the "equals 0" for a second, while we factor "x2 plus 5x plus 6".
x2 + 5x + 6 = (x + 3) (x + 2).
Now, if you want this expression to be equal to zero, that can only happen when 'x' is -2 or -3.
x2 + 5x - 120 can not be factored.
x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1
x2+5x-6 = (x+6)(x-1) when factored
x2-5x+4 = (x-1)(x-4) when factored
(x + 8)(x - 3)
x2-5x+4 = (x-1)(x-4) when factord
x2 + 5x - 120 can not be factored.
5(x2 + x + 1)
Since 5x is a factor of both terms, divide it. 5x3 + 5x = 5x(x2 + 1)
x2+5x+6 = (x+2)(x+3)
To factor the expression x^3 + 5x^2 + 6x, we first look for common factors among the terms, which is x. Factoring out x gives us x(x^2 + 5x + 6). Next, we factor the quadratic expression x^2 + 5x + 6 by finding two numbers that multiply to 6 and add up to 5, which are 2 and 3. Therefore, the factored form of x^3 + 5x^2 + 6x is x(x + 2)(x + 3).
x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1
x2-5x-36 = (x-9(x+4) when factored
x2+5x-6 = (x+6)(x-1) when factored
x2-5x+4 = (x-1)(x-4) when factored
x - 3
(x + 8)(x - 3)