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x2+8x = -3x2+5

4x2+8x-5 = 0

(2x+5)(2x-1) = 0

x = -5/2 or x = 1/2

Q: X2 plus 8x equals -3x2 plus 5?

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Assuming the 2 is meant to be a square this is the form: x2 - 3x2 = -2x2 + 8x + 5

x2+8x+9 = -7 x2+8x+9+7 = 0 x2+8x+16 = 0 (x+4)(x+4) = 0 Therefore: x = -4 and also x = -4 (they both have equal roots)

x2 + 8x - 6 = 0 x2 + 8x + 16 = 22 (x + 4)2 = 22 x + 4 = ± √22 x = -4 ± √22

x2 + x2 + x2 = (1 + 1 + 1)x2 = 3x2

2 this Domo

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In general, no.

2x^2 + 8x + 3 = 0

Assuming the 2 is meant to be a square this is the form: x2 - 3x2 = -2x2 + 8x + 5

no

x2+8x+9 = -7 x2+8x+9+7 = 0 x2+8x+16 = 0 (x+4)(x+4) = 0 Therefore: x = -4 and also x = -4 (they both have equal roots)

x=-0.7

x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0

x2 + 8x - 6 = 0 x2 + 8x + 16 = 22 (x + 4)2 = 22 x + 4 = ± √22 x = -4 ± √22

x2 + x2 + x2 = (1 + 1 + 1)x2 = 3x2

2 this Domo

x2 + 8x - 5 = 0 ∴ x2 + 8x + 16 = 21 ∴ (x + 4)2 = 21 ∴ x + 4 = ± √21 ∴ x = -4 ± √21

x2-8x=0 ( add 8x to both sides) x2 =8x (divide by x) x=8 ( x2divided by x equals x)