x2 - 8x + 32 = 0 (assuming)you can factor or use the quadratic equation.I recommend the quadratic equation.
No.
- 8x + 8x = 0 so question is meaningless.
8x + 3 = 35 8x = 32 x = 4
8x + 8=40 8x=40-8 8x=32 x=32/8 x=4
X= 1.567764363, -9.567764363
after applying quadratic formula x=-0.68 or x=7.32
x2+8x+12 = 0 When factorized: (x+6)(x+2) = 0 Therefore: x = -6 or x = -2
(2x - 1)(2x + 5)
Y-8x plus 9y equals 10y-8x.
8x plus 4y equals 5 is 8x + 4y = 5.
It will have two solutions because its a quadratic equation: x = -8.472135955 or x = 0.472135955
x2 - 8x + 32 = 0 (assuming)you can factor or use the quadratic equation.I recommend the quadratic equation.
x2-8x+12 = 0 (x-2)(x-6) = 0 x = -2 or x = -6
x^2 -8x-4=0 x=[8±√(64+16)]/2 x=(8±4√5)/2 x=4±2√5
To find the points of intersection on the x-axis, set y equal to zero and solve for x. So, 8x^2 - 26x + 15 = 0. This is a quadratic equation that can be factored or solved using the quadratic formula. Once you find the values of x, those are the points of intersection on the x-axis.
No.