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Xavier is twice as old as his sister Yolanda was when he was as old as she is now Their combined ages is 70 How old are they?
Wiki User
∙ 14y ago
Okay, so let's make Xavier x, and Yolanda y. We know that their combined ages are 70, so:
x + y = 70
Now, Xavier is twice as old as his sister Yolanda was when he was as old as she is now. To get how old Yolanda was when he was as old as she is now, we have how old she is now, minus the difference between their ages, which is y - (x - y). Xavier is twice as old as this, so:
x = 2(y - (x - y))
Take out the second set of brackets:
x = 2(y - x + y)
which is:
x = 2(2y - x)
Multiply out the brackets:
x = 4y - 2x
Now, we know that x + y = 70 from the first equation, so:
y = 70 - x
replace y in the equation above (x = 4y - 2x) with 70 - x and you get:
x = 4(70 - x) - 2x
Multiply out the brackets again:
x = 280 - 4x -2x
x = 280 - 6x
add 6x to both sides:
7x = 280
divide both sides by 7:
x = 40
So Xavier is forty. Their combined ages are 70, so Yolanda is thirty.
Wiki User
∙ 14y ago
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