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Q: Y equals xsquared plus 2x-3

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y=xsquared-4x+2

Quadratic - the degree is two.

If x = -7, then x3 = -343 so that 2x3 = -686 y = 2 then 15 y = 30 So 2x3 + 15y = -686 + 30 = -656

It can be simplified in the form of: 2x3+9x2-7x-34 = 0

y = -9

x+y

6

x = -7, y = 2 ⇒ 2x3 + 15y = 2 x (-7)3 + 15 x 2 = 2 x (-343) + 15 x 2 = -656

No real solutions. But if you want to find the imaginaries: x=.5(25-i(337)^.5) y=.5(25-i(337)^.5) x^.5= the square root of x

No... whenever you have an exponent on your varaible your graph is not liner. this is a parabola.

4y

a = 3 and y = 0

x = y = 0 ?

y=-10x-4

2

x = 14

x = -4 and y = 2

y equals x plus 4 when y equals 0 then x equals 2i i is the square root of negative 1

x = 2y = 4

x = -3, y = 7

(1, 9)

Y-8x plus 9y equals 10y-8x.

(3, 1)

(0, -3)

Their graphs are.