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the first rectangle is 8cm x 5cm the second rectangle has an area of half of 40 = 20 sq cm it could be 4cm x 5cm or 8cm x2.5cm or 10cm x 2cm or any pair of numbers whose product is 20 if you wanted the rectangles to be congruent ie have the same ratio of length to width then you need to employ Irrational Numbers the answer in this case is 8 divided by sqrt(2) for length and 5 divided by sqrt(2) for width or approximately 5.6568542494923801952067548968388cm x 3.5355339059327376220042218105242 cm

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โˆ™ 2009-03-05 13:59:20
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Q: You a rectangle has an area of 40 square cm and has a length of 8 cm and another rectangle is one-half the size of the other rectangle what is the width of the rectangle that is one-half the area of?
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