You are an isosceles triangle.
What is the sum of the measures of the exterior angles of a regular polygon with ten sides
a convex polygon has 6 sides . What is the sum of the measure of its interior angles?
The polygon will have 12 equal sides and each interior angle measures 150 degrees.
The polygon has eight (8) sides.
The 4 interior angles of a regular polygon with 4 sides which is a square each measures 90 degrees
6
The sum of the internal angles of a polygon of n sides is (n-2)*180 degrees.
The answer is 11 sides If a polygon with 10 sides the sum of the interior angles are 1440° So 1440°+180°= 1620°
All vertex angles (also called "interior angles") of a regular polygon have equal measures. If this regular polygon has n sides, then the sum of all the interior angles is 162° times n. The sum of the measures of all the interior angles of any polygon with n sides is (n-2) times 180°. So we have this equation 162n=(n-2)(180) which has solution n=20. So the polygon has 20 sides. Edwin McCravy
It will have 24 sides
13 sides
it has 24 sides.