If the number has a remainder of 2 when divided by 5, it must end in either 2 or 7. Because adding 10 to a number ending in 2 will not be a Prime number, it must end in 7. Because you will have a prime number if you subtract 10, it must be greater than 10. The possible numbers are:
17
27
37
47
The only one of these that is divisible by 3 is 27. If you subtract 10 from 27, you have 17, which is a prime number. If you add 10 to 27, you have 37, which is a prime number. The factors of 27 are 1, 3, 9, and 27, so it has only two factors other than 1 and itself. When divided by 5, the result is 5 remainder 2. Thus, 27 fits all the conditions.
No it has a reminder when it's divided by 7
Subtract the remainder which is left when the digital root is divided by 9.
419 Nachiket Joshi solution: LCM(7,6,5,4,3,2)=420 now subtract 1 frm answer ...............so the answer will be 419..... TRICK: Since the diff between the remainder and dividend is common(1 in this case ) u subtract 1 from the LCM
A number divided by 2 its reminder is 1, A number divided by 3 its reminder is 2, A number divided by 4 its reminder is 3, A number divided by 5 its reminder is 4, A number divided by 6 its reminder is 5, A number divided by 7 its reminder is 6, A number divided by 8 its reminder is 7, A number divided by 9 its reminder is 8, A number divided by 10 its reminder is 9 what is that number?
58
2.3333
79.2
No, 96 divided by 8 does not have a remainder. When you divide 96 by 8, the result is 12, which is a whole number. This means that 96 is evenly divisible by 8.
Divisible means "able to be divided." Something that is divisible can be divided into parts or portions or separated into pieces.
6.6667
It reminds me nothing in particular that I can remember
In mathematics, numbers that can be divided without a remainder are referred to as divisible numbers. For example, any integer can be divided by its factors, such as 2, 3, or 5, if those numbers evenly divide it. Additionally, whole numbers can be divided by themselves and 1 without a remainder. Essentially, any number can be divided evenly by its divisors.