H(w)>0
ax2 + bx + c = 0 where a, b and c are constants and a is not 0.
Car 54 Where Are You?
8m Let the width of the table be w; then its length is w + 2. Area = length x width 80 = (w + 2)w w2 + 2w - 80 = 0 (w + 10)(w - 8) = 0 w = -10 or 8 As the width must be positive, it is 8m.
w x w + 6 = 135 w2 + 6w - 135 =0 Ie (w - 9)(w + 15) = 0 width = 9m (length = 15m)
0 calories in water
0 Degrees Celsius at which Water Freezes
0 calculators in a warturtle!
0= Freezing Point of water on Celsius Scale.
import java.io.*; class AvgWordSent { protected static void main()throws IOException { BufferedReader in=new BufferedReader(new InputStreamReader(System.in)); System.out.print("Enter the Sentence: "); String s=in.readLine(); byte a=0,b=0; float c=0; for(byte i=0;i<s.length();i++) { if(s.charAt(i)==' ') a++; } String w[]=new String[a+1]; for(byte i=0;i<=a;i++) w[i]=""; for(byte i=0;i<s.length();i++) { if(s.charAt(i)==' ') { b++; continue; } w[b]+=s.charAt(i); } b++; for(byte i=0;i<=a;i++) c+=w[i].length(); System.out.print("Average no. of words= "+(c/b)); } }
If x ≡ w mod 357 then: x = 357k + w for some integer k. Now 357 = 21×17, and w = 17n + c for some integers n ≥ 0 and 0 ≤ c < 17 → w ≡ c mod 17 This gives: x = 21×17×k + 17n + c → x = 17(21k + n) + c → x = 17m + c where m = 21k + n (is an integer) → x ≡ c mod 17 → the remainder when the number is divided by 17 is the same as the remainder when the original remainder w is divided by 17.
Water Freezes at 0 degrees celsius
0 = freezing point of water on Celsius scale
w2-3w = 0 w(w-3) = 0 w = 3 or w = 0
This is the way: [W] [W] [W] [C] [I] [C] [C] [R] [C] W = Wood planks C = Cobblestone I = Iron ingot R = Redstone (dust)
No, w-w = 0. Any number minus itself is zero. On the other hand, 0 - w = -w.
49w2 - 25w = 0 factor out a w w(49w - 25) = 0 set the expression in the parenthesis to that 0 as w already = 0 49w - 25 = 0 49w = 25 w = 25/49 ============so w = 0 -------- w = 25/49 --------------