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H(w)>0
ax2 + bx + c = 0 where a, b and c are constants and a is not 0.
8m Let the width of the table be w; then its length is w + 2. Area = length x width 80 = (w + 2)w w2 + 2w - 80 = 0 (w + 10)(w - 8) = 0 w = -10 or 8 As the width must be positive, it is 8m.
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w x w + 6 = 135 w2 + 6w - 135 =0 Ie (w - 9)(w + 15) = 0 width = 9m (length = 15m)