The answer is: x-y = 11 3x+10y = -6
10y
8x - 10y = 27x - 5y = 13First, we need to eliminate one of the variables. For this, we would like to have them with the same coefficient but different sign. We can do this if we multiply by -2 the second equation.8x - 10y = 2-2(7x - 5y) = -2(13)8x - 10y = 2-14x +10y = -26Now, we can add both equations, and solve for x.(8x - 10y) + (-14x + 10y) = (2) + (-26)(8x - 14x) +(-10y + 10y) = (2 - 26)-6x = - 24-6x/-6 = - 24/-6x = 4Substitute 4 for x in the first equation:8x - 10y = 28(4) - 10y = 232 - 10y = 232 - 32 - 10y = 2 - 32-10y = -30-10y/-10 = -30/-10y = 3Thus, the solution of the system is (4, 3).Check:
Y=-1/2(x)
x = 2, y = 1
y = ½ (6y = 3)
10y = 5 y = 5/10 Therefore, y = 0.5
y2 + 10z - 10y - yz = y2 - 10y - yz + 10z = y(y - 10) - z(y - 10) = (y - 10)(y - z)
The answer is: x-y = 11 3x+10y = -6
y= 3/6 which reduces to 1/2
y=(x+2)/(x+10) xy+10y=x+2 xy-x=2-10y x(y-1)=2-10y x=(2-10y)/(y-1)
10y
Write out equation - 10y - 5x= - 20 Negate equation 10y + 5x = 20 Isolate y variable 10y = - 5x + 20 Divide equation by 10 y= -1/2x + 2
4x-10y=11 4x=11+10y 10y+11=4x 10y=4x-11 y=(4/10)x-(11/10) y=(2/5)x-(11/10)
15y+14=2(5y+6) 15y+14=10y+12 15y+14-14=10y+12-14 15y=10y-2 15y-10y=10y-2-10y 5y=-2 y=-2/5
you have to bring the "y" to one side. 10y - 6 = 2 + 4y 10y-4y = 2 + 6 6y = 8 y = 8/6 If you substitute 8/6 into y you will find that 8/6 is the answer
10y-3=4y+6 10y = 4y + 9 6y = 9 y = 9/6 y = 3/2 y = 1.5