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The Answer is 43x-15 because you can only combine like terms (as in 2 and 2, or 2x and 2x, but not 2 and 2x
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Factor 14x2 plus 29x - 15?
(2x+5)(7x-3)=14x2 +29x-15
- -x plus 15?
--x + 15 = x + 15
What is 1 half plus 1 fourth plus 1 eighth plus 1 sixteenth?
15/16
What does 15--13 equal 15 --13 equals 28 because a minus and a minus equals a plus so the equation is actually 15 plus 13 equals 28?
Yes that is correct
10 plus the quotient of a number and 15?
10 + 15a * * * * * No! It is 10 + n/15
Factor the trinomial below 14x plus 29x-15?
Assuming you mean 14x2... (7x - 3)(2x + 5)
Factor 14x2 plus 29x - 15?
(2x+5)(7x-3)=14x2 +29x-15
What is 6x plus 15 plus 14x plus 8?
20x + 23
How do you factor 3x squared minus 14x plus 15?
3x^2 -14x +15 = (3x-5)(x-3)
Factor as a polynomial in descending order14x2 plus 29x - 15?
(7x-3)(2x+5) 14x2 + 29x - 15, write 29x = 35x - 6x = 14x2 - 6x + 35x - 15 = (14x2 - 6x) + (35x - 15) = 2x(7x - 3) + 5(7x - 3) = (7x-3)(2x+5)
What is Negative 7x plus 3 equals negative 15 divided by 2 help?
x = 1.5 because -7x + 3 = -15/2 -14x + 6 = -15 (x2) -14x + 21 = 0 (+15) 21 = 14x (+14x) 3 = 2x (/7) 1.5 = x
Factor the trinomial and enter your answer below Write each factor as a polynomial in descending order14x2 plus 29x - 15?
14x2 + 29x - 15= 14x2 + 35x - 6x - 15= 7x(2x + 5) - 3(2x + 5)= (2x + 5)(7x - 3)
Factor 5x2 plus 14x - 3?
5x2+14x-3 -15. 15*-15x2-x+15x-3[5xx x] [3*5x 3]x(5x-1)+3(5x-3)Answer: (5x-1)(x+3)
What is 8x 15?
15=8x^2-14x
Solve the equation by factoring 15 equals 8x2-14x?
15 = 8x2 - 14x; whence, 8x2 - 14x - 15 = (2x - 5)(4x + 3) = 0. Therefore, x = 5/2 or -3/4.
What is the factorization of the trinomial 14x square plus 29x-15?
If you just want the answers, the factors are: (2x+5)(7x-3)=0 and the roots/x-intercepts/zeros are: x= 3/7 and x= -2.5 If you want to see the work... ax^2 + bx + c = 0 14x^2 + 29x - 15 = 0 This is type 4 factorization... so you need to find numbers that multiply to give you the product of a and c (a*c), and add to give you b. so, a*c = (14)*(- 15) = -210, and b = 29 the numbers that would satisfy these requirements are +35, and - 6 so, here's the original equation: 14x^2 + 29x - 15 = 0 you carry down the first and third terms (a and c) and place them in the same places 14x^2 - 15 = 0 you then take the numbers you found, 35, and -6, and stick them with x's in the equation... 14x^2 +35x -6x - 15 = 0 you then factor out the largest factor of the first two terms, which is 7x 7x(2x+5) and then you repeat for the next two terms, the largest factor is -3 -3(2x+5) so here's your new equation: 7x(2x+5) -3 (2x+5) = 0 note that the two binomials are the same... take one of the binomials (2x+5)... this is one of your factors... and then the others terms (the coefficients) and put them into one binomial (7x-3) your other factor... so, your your two factors are (2x+5)(7x-3)=0 2x=-5 x= -2.5 7x=3 x=3/7 the x values are your roots/zeros/x-intercepts.
What does x equal in 46-3 plus x plus x plus x plus x plus x plus x plus x-15 equals 42?
The problem can be written as:46-3+7x-15 = 4243+7x-15=427x + (43-15) = 427x + 28 = 427x = 42 - 287x = 14x = 14/7 = 2
