(r3-3r2-5r-3)/(r-1)
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3x + 2x = 5x. 5x= (-4) X = (-4)/5 x= -0.8
Then x = 6 Therefore; 5x + 3 = 33 First you have to solve the value of X: 8X + 5X + 2X +4X = 114; OR 19x = 114. When you divide both sides of the equation by 19 to solve for X, you find that X = 6. Ergo, 5X + 3 = 30 + 3 = 33; hence, 5X + 3 = 33.
y = 2x -1 y = 5x -13 So: 5x -13 = 2x -1 5x -2x = 13 -1 3x = 12 x = 4 and by substituting y = 7
Here is how you solve this problem... 5x*4-3x*5*2x-9= (Combine like-terms) 5x-3x*2x= 2x*2x=(2x)2 (Add the rest of the problem) (2x)2*4*5-9=(2x)2*20-9 (2x)2*11 (2x)2 *11= your answer
5x+2x=7x2x + 5x = 7x