2x + 1 = -5 so 2x = -6 so that x = -3 Then 3x - 4 = 3*(-3) -4 = -9 - 4 = -13
If: 12 = 2y+x then y = -1/2x+6 So: y = 2x+4 and y = -1/2x+6 which means that they are perpendicular lines
If 3x + 3 = 2x + 6 then 3x - 2x = 6 - 3 x = 3
5x - 4 = 3x + 6 5x - 3x = 6 + 4 2x = 10 x = 5
-4
2x -6 = 4 then 2x = 4 +6 x=10/2 = 5
5
x = 3 y = 4 2x + y - 1 = (6) + (4) - 1 = 9
2x + 4 = 10 2x = 10 - 4 = 6 2x = 6 x = 6/2 = 3
2x-y = 4 and 2y = 4x-6 pick either equation and solve for one of the variables the first equation: y = -4 + 2x plug in the value of variable you solved for into the other equation 2(-4 + 2x) = 4x -6 then solve -8 + 2x = 4x-6 -2 = 2x x= -1 then plug in the value you have found into either original equation to find the value of the other variable 2(-1) - y = 4 -2 - y = 4 -y = 6 y = -6
6
6
6 + 2x = x - 6 2x - x = -6 -6 x = -12
2x + 1 = -5 so 2x = -6 so that x = -3 Then 3x - 4 = 3*(-3) -4 = -9 - 4 = -13
2x - 4 = -10 2x = -10 +4 2x = -6 x = -3
4 - 2x = 10 -2x = 10-4 -2x = 6 -x = 3 x = -3
2x+3y = 6 2x+3(0) = 6 2x = 6 x = 6/2 x = 3