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What else can I help you with?
What is 3 x 3 x 3 x 3 x 3 x 3 in exponential form and then solve?
3^6 = 729
3 to the power of 3?
27 3 to the power of 3 3 x 3 x 3 (3 x 3) x 3 9 x 3 27
What is the LCM of 54 and 210 in prime factorazation?
2 x 3 x 3 x 3 = 54 2 x 3 x 5 x 7 = 210 2 x 3 x 3 x 3 x 5 x 7 = 1890, the LCM
What are the prime factors of 216 288 360?
2 x 2 x 2 x 3 x 3 x 3 = 216 2 x 2 x 2 x 2 x 2 x 3 x 3 = 288 2 x 2 x 2 x 3 x 3 x 5 = 360
What is the prime factorization for 6480?
2 x 2 x 2 x 2 x 3 x 3 x 3 x 3 x 5 = 6480
10g equals how many 500 mg?
20 x 500 mg = 10g or 10g = 500mg x 20
What is the percentage strength of an ointment if one mixes 10g of hydrocortisone into aquaphor to make 400g?
10g/410g X 100 = 2.4 2.5 %
What mass of NH3 you prepared from the reaction of 10g of N2 with excess H2?
I had to do this problem on a sample exam I got from the University of South Carolina. It has to do with a stoichiometry reaction. If I got the answer wrong, I apologize but this is how I did it. I'll use 2 approaches so you can understand all the concepts going into it. And forget about the "excess H_2" so it doesn't throw you off. First write a balanced equation of the reactants and product: N_2 + 3H_2 -----> 2NH_3 N_2 = 10g 10g of N_2 x [1 mol N_2 / (14.0067x2)] x (3 mol H_2 / 1 mol N_2) x [(1.0079x2) / 1 mol H_2] so, 10 x (1 / 28.0134) x (3) x (2.0158), is 10 x (.03569) x (3) x (2.0158) = 2.158 grams of H_2 Since we have 10g of N_2, we can add the two numbers and find out the mass of ammonia. 10g + 2.158 = 12.158g, or 12 g NH_3. Similarly we can substitute the ammonia (NH_3) for the H_2 in the equation above and get the same answer. 10g of N_2 x [1 mol N_2 / (14.0067x2)] x (2 mol NH_3 / 1 mol N_2) x [(14.0067 + (1.0079 x 3)) / 1 mol NH_3] so, 10 x (1 / 28.0134) x (2) x (17.0304), is 10 x (.03569) x (2) x (17.0304) = 12.158 g, or 12 g NH_3
How do you restore a table deleted from oracle 10g?
If you are on 10g or later and the recycle bin feature is turned on, you can use the FLASHBACK TABLE x TO BEFORE DROP command, where x is the name of the table. If it is not there, or the recycle bin feature is not available, you will have to restore the table from a backup.
How do you factor 5x-25 plus 2gx-10g?
5(X - 5) + 2g(X - 5)-------------------------------all the factoring I can see
How many atoms are in 10g of Fe?
To determine the number of atoms in 10g of Fe, you first need to calculate the number of moles of Fe using its molar mass (55.85 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms in those moles of Fe. Finally, multiply the number of moles by Avogadro's number to get the total number of atoms in 10g of Fe.
What is the maximum data transfer for 10GBASE-X?
10G networks transfer at a maximum of 10 gigabits per second.
What is 0.01kg in grams?
1 kg = 1000g (kilo=1000)0.01 kg = 0.01 x 1000g = 10g
How many moles in 10g of iodine?
To calculate the number of moles in 10g of iodine, you need to first determine the molar mass of iodine (I), which is 126.9 g/mol. Then, you can use the formula: moles = mass / molar mass. So, moles = 10g / 126.9 g/mol ≈ 0.079 moles of iodine.
How much sample of 10g of tritium with half life of 12.32 after 2 half lives?
After 2 half-lives (two half-lives of tritium is 12.32 x 2 = 24.64 years), the initial 10g sample of tritium would have decayed by half to 5g.
Why does 10g of nitrogen gas contain the same number of molecules as 10g of carbon molecules?
No, they do NOT contain the same number of particles (either molecules N2 or atoms C): there molecular or atomic mass is different.Look at this:10g N2 / 28 (g/mole N2) x 6.022x1023 (molecules N2/mole N2) = 2.15 x1023 molecules N210g C / 12 (g/mole C) x 6.022x1023 (atoms C/mole C) = 5.02 x1023 atoms C
How many atoms are in 10g of nitrogen?
10 grams nitrogen (1 mole N/14.01 grams)(6.022 X 1023/1 mole N) = 4.3 X 1023 atoms of nitrogen ======================
