(3x-2)(2x+7) is the same as 6x^2 +17x -14 when the brackets are multiplied out
6x + 9x^3 = 3x*(2 + 3x^2)
(3x-2)(2x+7) is the same as 6x^2 +17x -14 when the brackets are multiplied out
5x + 8 = 3x + 25x - 3x = 2 - 82x = -6x = -6/2x = -3Check:5(-3) + 8 = 3(-3) + 2-15 + 8 = -9 + 2-7 = -7
3x - 6 = -3x + 36Add 3x to each side:6x - 6 = 36Add 6 to each side:6x = 42Divide each side by 6:x = 7
3x + 7 = 6x - 2 Rearranging gives 6x - 3x = 7 + 2 3x = 9 x = 3
6x-7 = 3x+5 6x = 3x+12 (subtracting -7) 3x=12 (subtracting 3x) x=4 (dividing by 3)
6x+4=3x+12 => 6x-3x=12-4 => 3x=8 => x=8/3=2.666...
(3x-2)(2x+7) is the same as 6x^2 +17x -14 when the brackets are multiplied out
(3x-2)(2x+7) is the same as 6x^2 +17x -14 when the brackets are multiplied out
6x + 9x^3 = 3x*(2 + 3x^2)
(3x-2)(2x+7) is the same as 6x^2 +17x -14 when the brackets are multiplied out
If: 3x^2 = 6x+4 Then: 3^2 -6x-4 = 0 Divide all terms by 3: x^2 -2x-4/3 = 0 Completing the square: (x-1)^2 -7/3 = 0 => (x-1)^2 = 7/3 or as 21/9 If: (x-1)^2 = 21/9 Then: x = 1 +/- (square root 21) over 3 which are the exact solutions
-3(x + 2)(x + 4)
(3x-2)(2x+7) is the same as 6x^2 +17x -14 when the brackets are multiplied out
xx+3x+7=6x+18 xx+3x+7-(6x+18)=6x+18-(6x+18) xx-3x-11=0 Factors of -11: 1,-11 -1,11 Doesn't factor evenly, use quadratic
9x-19=6x+2 so 3x=21 and x=7