3xy-2y=0 3xy=2y y=2y (3x) y/2y=3x 1/2=3x multiply across by 2 1=6x 1/6=x therefore substituting x=1/6 into 3xy-2y; 3(1/6)y-2y=0 1/2y=2y y=2y/0.5 0.5 aka 1/2 y=1
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Put in this form.......Y = mX + bb = Y intercept.3X - 2Y = 6- 2Y = - 3X + 6Y = (3/2)X - 3================
If you mean: 3x+2y = 16 then it is y = -1.5x+8
3x+2y+x
Put in function form. 3X - 2Y = 5 - 2Y = - 3X + 5 Y = 3/2X - 5/2 Y intercept = - 5/2
If you mean: 3x+y-x+y then it is an algebraic expression that can be simplified to 2x+2y