lAdY THiNKS iTS 12.....EXPlAiN::3X-1=11(3*x)-1=11x=4(3*4)-1=11(12)-1=11so sub w/ all XX2+X(4*2)+4(8)+4answer= 12If you with X2 mean X²:4²+4=20
If: 3x-1 = 11 Then: 3x = 11+1 So: x = 12/3 = 4
3x - 1 = 11 so 3x = 12 so x = 4, so x^2 + x = 16 + 4 = 20 3x=12 so therefore x=4 x2 + x = 16 + 4 = 20
The factors of 484 are 1, 2, 4, 11, 22, 44, 121, 242, and 484. The factor pairs of 484 are 1 x 484, 2 x 242, 4 x 121, 11 x 44, and 22 x 22. The proper factors of 484 are 1, 2, 4, 11, 22, 44, 121, and 242, or if the definition you are using excludes 1, they are 2, 4, 11, 22, 44, 121, and 242. The prime factors of 484 are 2, 2, 11, and 11. Note: There is repetition, so usually only the distinct prime factors are given. The distinct prime factors of 484 are 2 and 11. The prime factorization of 484 is 2 x 2 x 11 x 11 or in exponential form 2^2 x 11^2.
(4, 10); m = -1/4 y = mx + b replace y with 10, m with -1/4, and x with 4 10 = (-1/4)4 + b 10 = -1 + b add 1 to both sides 11 = b y = (-1/4)x + 11
1 x 44, 2 x 22, 4 x 11, 11 x 4, 22 x 2, 44 x 1 = 44
2.75 ÷ 1/4 = 2.75 x 4/1 = 11 Then the number of quarters in 2.75 ÷ 1/4 is the number of quarters in 11, which is: 11 ÷ 1/4 = 11 x 4/1 = 44
To Find: x^2 + x Procedure: Given: 3x - 1 = 11. Solving, we have 3x - 1 + 1 = 11 +1 3 x = 12 x = 4 Therefore, x^2 + x = 4^2 + 4 = 16 + 4 = 20 ===================
1 x 44, 2 x 22, 4 x 11, 11 x 4, 22 x 2, 44 x 1.
1 x 44, 2 x 22, 4 x 11, 11 x 4, 22 x 2, 44 x 1.
1 x 44, 2 x 22, 4 x 11, 11 x 4, 22 x 2, 44 x 1.
3x-1=11 (3x-1)+1=11+1 3x=12 (3x)x(1/3)=12 x (1/3) x=4 x^2+4 16+4 =20
1, 2, 4, 11, 22, 44.
11 x 1/4 = 11/4 = 2 and 3/4 .
(4 x 11) - (1 x 11) = 3 x 11 = 33
3x-1=11 solves to x=4. Plug in 4 to get 42+4. The answer is 20.
1, 2, 4, 8, 11, 22, 44, 88: (1 x 88, 2 x 44, 4 x 22, 8 x 11)