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6 B 2 an O in C?

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6 balls to an over in cricket

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What letter should be next A Z E BI Y O?

C. Every other letter is a vowel A E I O. The ones in between are Z B Y So z is to b as y is to C. So I think it's C


What is the next letter in the following series A Z E B you Y O?

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How do l write complete qbasic program to compute quadratic equation whose sides are A B C and print out your result?

Exercise : Write a program to solve quadratic equations (ax^2 + bx + c), using a subroutinesub quadratic(a as double, b as double, c as double, indicator as long, root1 as double, root2 as double) Input parameters are a, b, c. Output parameters are :indicator (= 0 , two identical roots, = 1, two distinct real roots, = 2 , complex roots ) For real roots : they are stored in "root1" and "root2". For complex roots : root1 = real part, root2 = imaginary part. Ans : DEFLNG I-N DEFDBL A-H, O-Z L20: INPUT " Coefficients a,b,c (a*x^2+b*x+c) "; a, b, c CALL quadratic(a, b, c, iflag, r1, r2) IF iflag = 0 THEN PRINT "2 Identical roots "; r1 ELSEIF iflag = 1 THEN PRINT "2 distinct real roots "; r1; r2 ELSE PRINT "Complex root" PRINT "real part "; r1; "imaginary part "; r2 END IF GOTO L20 END SUB quadratic (a AS DOUBLE, b AS DOUBLE, c AS DOUBLE, indicator AS LONG, root1 AS DOUBLE, root2 AS DOUBLE) rem rem Input parameters: rem a*x*x + b*x + c rem rem Output parameters: rem indicator = 0 two identical roots, = 1 two distinct real roots, = 2 , complex roots. rem root1, root2 stores the real and imaginary part when complex roots occur. rem discrim = b * b - 4. * a * c IF discrim > 0 THEN dummy = SQR(discrim) indicator = 1 root1 = (-b + dummy) / (2. * a) root2 = (-b - dummy) / (2. * a) ELSEIF discrim = 0 THEN indicator = 0 root1 = -b / (2. * a) root2 = root1 ELSE indicator = 2 dummy = SQR(-discrim) root1 = -b / (2. * a) root2 = dummy / (2. * a) END IF END SUB


How many letters have line symmetry and rotational symmetry?

16 letters have line symmetry: A, B, C, D, E, H, I, K, M, O, T, U, V, W, X, Y 6 letters have rotational symmetry: H, I, N, O, S, X, Z 4 letters have both: H, I, O, X


What is the number of distinguishable permutations of the letters in the word oregon?

360. There are 6 letters, so there are 6! (=720) different permutations of 6 letters. However, since the two 'o's are indistinguishable, it is necessary to divide the total number of permutations by the number of permutations of the letter 'o's - 2! = 2 Thus 6! ÷ 2! = 360

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