C. Every other letter is a vowel A E I O. The ones in between are Z B Y So z is to b as y is to C. So I think it's C
C
Oh, what a lovely question! To create a QBasic program to compute a quadratic equation with sides A, B, and C, you can use the formula x = (-B ± SQR(B^2 - 4AC)) / 2A. First, you'll need to prompt the user to input values for A, B, and C. Then, you can calculate the roots of the equation using this formula and print out the results. Remember, mistakes are just happy little accidents in programming, so take your time and enjoy the process!
16 letters have line symmetry: A, B, C, D, E, H, I, K, M, O, T, U, V, W, X, Y 6 letters have rotational symmetry: H, I, N, O, S, X, Z 4 letters have both: H, I, O, X
360. There are 6 letters, so there are 6! (=720) different permutations of 6 letters. However, since the two 'o's are indistinguishable, it is necessary to divide the total number of permutations by the number of permutations of the letter 'o's - 2! = 2 Thus 6! ÷ 2! = 360
6 Balls to an Over in Cricket
6 balls to an over in cricket
6 b in a O
3rd Rock from the Sun - 1996 B-D-O-C- 6-7 was released on: USA: 12 December 2000
How many bowls to an over in cricket. There are 6 bowls in an over in cricket.
The Cleveland Show - 2009 B-M-O-C- 3-18 is rated/received certificates of: Netherlands:6
I assume that the "diameter of a triangle" means the diameter of the smallest circle containing it. Assume the triangle has sides a, b and c and angles A, B and C (where angle A is opposite side a etc.). Calculate angle A from the law of cosines. Then: a^2 = b^2 +c^2 - 2*b*c*cos(A) so: A = arccos((b^2 + c^2 - a^2)/(2*b*c)) -------------------(1) Then, using the usual construction for finding the center, O, of the circumscribed circle (i.e. a perpendicular bisectors of each side is constructed and all three meet at point O) we can draw the radius from O to A. This will divide angle A into two smaller angles (in some cases one angle will be larger than A and the other will be negative, but they will still add up to angle A). Using simple trigonometric formulas we can calculate angle A by adding the two together. The result then is: A = arccos(b/(2*r)) + arccos(c/(2*r)) -----------------------------(2) If we then equate the right hand sides of (1) and (2) we get an equation involving a, b, c and r. These can be solved to find r in terms of a,b and c. I used the easy way using Maple and got the result shown below. r = abs[sqr(-b^4+2*b^2*c^2+2*b^2*a^2-c^4+2*c^2*a^2-a^4)*a*c*b]/ [ b^4-2*b^2*c^2-2*b^2*a^2+c^4-2*c^2*a^2+a^4] The diameter is, of course, 2*r. This answer checks the cases for an equilateral triangle and for a 3,4,5 right triangle, each of which is easy to do by much simpler methods.
The O-C- - 2003 The Chrismukkah That Almost Wasn't 2-6 is rated/received certificates of: Australia:PG USA:TV-PG
S = Stimulas O = Organism B = Behaviour C = Consiquence
The White Shadow - 1978 B-M-O-C- 3-9 was released on: USA: 2 February 1981
photosynthesis- 6H O + 6O under the presence of sunlight and clorophyll=C H O 2 2 6 12 6
According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 2 words with the pattern C-O-B-O-. That is, eight letter words with 1st letter C and 3rd letter O and 5th letter B and 7th letter O. In alphabetical order, they are: cookbook crowboot