C. Every other letter is a vowel A E I O. The ones in between are Z B Y So z is to b as y is to C. So I think it's C
C
Exercise : Write a program to solve quadratic equations (ax^2 + bx + c), using a subroutinesub quadratic(a as double, b as double, c as double, indicator as long, root1 as double, root2 as double) Input parameters are a, b, c. Output parameters are :indicator (= 0 , two identical roots, = 1, two distinct real roots, = 2 , complex roots ) For real roots : they are stored in "root1" and "root2". For complex roots : root1 = real part, root2 = imaginary part. Ans : DEFLNG I-N DEFDBL A-H, O-Z L20: INPUT " Coefficients a,b,c (a*x^2+b*x+c) "; a, b, c CALL quadratic(a, b, c, iflag, r1, r2) IF iflag = 0 THEN PRINT "2 Identical roots "; r1 ELSEIF iflag = 1 THEN PRINT "2 distinct real roots "; r1; r2 ELSE PRINT "Complex root" PRINT "real part "; r1; "imaginary part "; r2 END IF GOTO L20 END SUB quadratic (a AS DOUBLE, b AS DOUBLE, c AS DOUBLE, indicator AS LONG, root1 AS DOUBLE, root2 AS DOUBLE) rem rem Input parameters: rem a*x*x + b*x + c rem rem Output parameters: rem indicator = 0 two identical roots, = 1 two distinct real roots, = 2 , complex roots. rem root1, root2 stores the real and imaginary part when complex roots occur. rem discrim = b * b - 4. * a * c IF discrim > 0 THEN dummy = SQR(discrim) indicator = 1 root1 = (-b + dummy) / (2. * a) root2 = (-b - dummy) / (2. * a) ELSEIF discrim = 0 THEN indicator = 0 root1 = -b / (2. * a) root2 = root1 ELSE indicator = 2 dummy = SQR(-discrim) root1 = -b / (2. * a) root2 = dummy / (2. * a) END IF END SUB
16 letters have line symmetry: A, B, C, D, E, H, I, K, M, O, T, U, V, W, X, Y 6 letters have rotational symmetry: H, I, N, O, S, X, Z 4 letters have both: H, I, O, X
360. There are 6 letters, so there are 6! (=720) different permutations of 6 letters. However, since the two 'o's are indistinguishable, it is necessary to divide the total number of permutations by the number of permutations of the letter 'o's - 2! = 2 Thus 6! ÷ 2! = 360
6 Balls to an Over in Cricket
6 balls to an over in cricket
3rd Rock from the Sun - 1996 B-D-O-C- 6-7 was released on: USA: 12 December 2000
6 b in a O
How many bowls to an over in cricket. There are 6 bowls in an over in cricket.
The Cleveland Show - 2009 B-M-O-C- 3-18 is rated/received certificates of: Netherlands:6
Since H6 = +1 x6 = +6 and O= -2 . You are left with +4, therefore each C atom has -2
I assume that the "diameter of a triangle" means the diameter of the smallest circle containing it. Assume the triangle has sides a, b and c and angles A, B and C (where angle A is opposite side a etc.). Calculate angle A from the law of cosines. Then: a^2 = b^2 +c^2 - 2*b*c*cos(A) so: A = arccos((b^2 + c^2 - a^2)/(2*b*c)) -------------------(1) Then, using the usual construction for finding the center, O, of the circumscribed circle (i.e. a perpendicular bisectors of each side is constructed and all three meet at point O) we can draw the radius from O to A. This will divide angle A into two smaller angles (in some cases one angle will be larger than A and the other will be negative, but they will still add up to angle A). Using simple trigonometric formulas we can calculate angle A by adding the two together. The result then is: A = arccos(b/(2*r)) + arccos(c/(2*r)) -----------------------------(2) If we then equate the right hand sides of (1) and (2) we get an equation involving a, b, c and r. These can be solved to find r in terms of a,b and c. I used the easy way using Maple and got the result shown below. r = abs[sqr(-b^4+2*b^2*c^2+2*b^2*a^2-c^4+2*c^2*a^2-a^4)*a*c*b]/ [ b^4-2*b^2*c^2-2*b^2*a^2+c^4-2*c^2*a^2+a^4] The diameter is, of course, 2*r. This answer checks the cases for an equilateral triangle and for a 3,4,5 right triangle, each of which is easy to do by much simpler methods.
The O-C- - 2003 The Chrismukkah That Almost Wasn't 2-6 is rated/received certificates of: Australia:PG USA:TV-PG
A)O B) O to power of ((2+)) C) O to power of ((3+)) D) O to power of ((2-)) E) O to power of ((+))
S = Stimulas O = Organism B = Behaviour C = Consiquence
The White Shadow - 1978 B-M-O-C- 3-9 was released on: USA: 2 February 1981