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6 times an integer minus 5 equals the square of the integer. find the integer?
Wiki User
∙ 14y ago
If we write the problem as 6x-5=x2, then we can write in the form of ax2+bx+c: -x2+6x-5. Then we can use the quadratic equation, x = (-b ± √(b2 - 4ac))/2a, and put in our own values to get the equation x = 3 ± 2. Therefore, x1= 1 and x2=5.
Wiki User
∙ 14y ago
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