The equation is P=C(1+r)^t; where C is the money invested, r is the rate(change from percent to decimal form), and t is the time.
So plug in the numbers to get: P=800(1+.06)^10
The answer is 1432.678, I would round it to $1432.68
If 1500 dollars is invested at an interest rate of 3.5 percent per year compounded continuously, after 3 years it's worth $1666.07, after 6 years it's $1850.52, and after 18 years it's worth $2816.42.
First include a unit of currency. I will use pounds, but if the answer is in dollars, simply replace the sign at the front of this sum to a dollar sign. The sum you are looking for is: £120000 x 1.0410 Rounded to the nearest penny (or cent, as appropriate), this is equal to £177629.31.
$10,000 times (1.1)3 = $13,310
1000 x (1.025)8 which is $1218.40.
That completely depends on what rate of interest you can expect your investment to earn, and how often you can expect the investment interest to be compounded. The assumed rate of interest has more effect on the final value than even the annual payment has, yet the question ignores it completely.
$280.51
If the interest is compounded annually, then the first interest payment isn't added until the end of the first year. Until then, the investment is worth exactly $15,000.00 .
$125 times (1.08)14 = $367.15 (rounded)
4000 x (1.0610) = $7163.39
You would need 9687 dollars.
4 years exactly.
If compounded and assuming the amount was 3180 dollars, it would be 784 dollars.
Simple interest compounded annually and reinvested will yield 619173.64 before taxes.
39,337.20
If 1500 dollars is invested at an interest rate of 3.5 percent per year compounded continuously, after 3 years it's worth $1666.07, after 6 years it's $1850.52, and after 18 years it's worth $2816.42.
100 x (1.05)4 = $121.55
1000 x (1.01)12 = $1126.83