It is slope intercept form. The equation for slope intercept form is y=mx+b which is like your equation y=5x+6
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5x+8y = 40 8y = -5x+40 y = -5/8x+5 in slope intercept form
y = x + 2 Slope-intercept form is y = mx + b The slope, m, would be 1 and the y-intercept, b, would be 2
== == y = -x + 5
It is: y = -0.4x+1 when in slope intercept form.
y = -1.2x-3 in slope intercept form
Slope-Intercept Form: y = -2x +1
y = 6x+8 is already in slope intercept form
Solving the equation for "y" gives you the slope-intercept form.
It is: y = -7x+1 in slope intercept form
Yes, that is the slope intercept form of the equation for a straight line.
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y= -4x + 10 Slope intercept form is y=mx+b
Slope-intercept form
y = 3x + 3 is the 'slope/intercept' form. In the general eq'n of a straight line ; y = mx + c ; The slope(m) is the coefficient of 'x' and the constant(c) is the intercept on the y-axis. So for the given eq'n , The slope is '3' and and the intercept is also '3'.
That is slope-intercept form of a line.