Time in Distance 1+ time in distance 2= 22
let the 1st Distance be x
2nd Distance = 500-x
time = distance / speed
x/10 + (500-x)/50= 22
LCM = 50
multiply equation by 50
5x+500-x=1100
4x=600
x=150 m
150 m at 10m/s
350 m at 50m/s
In all he will cover 40 km. To do so at an average speed of 10 kph means his total journey will take 4 hours. He has taken 3hr 20 min for the first part (30km @ 9kph), so he has 40 min to cover the final 10km. Required speed is therefore 10 x 60/40 ie 15 kph.
Speed X journey time. (Time actually moving).
The time taken depends on the speed at which the journey is undertaken. And the speed depends on a number of factors. Amongst these are the mode of transport, road conditions including weather, speed limits, traffic, whether or not the journey is non-stop.
Everyone pays the same fare on a train journey. The total amount is proportional to the number of people on the train.
The plane will take 5.5 hours or 5 hours and 30 minutes to complete the journey.
plese help me
Mercury
Mercury completes its orbit around the Sun faster than any other planet in our solar system.
If a train is making a journey of 567 miles and completes the journey in 3 hours and 7 minutes, how fast was it going.
the planet which completes its journey first is mercury i think
Earth spins on its axis for about 365/366 times while it completes one journey.
An orbit is the path followed by a planet as it travels regularly round the Sun. The Earth follows an orbit and completes one journey round its orbit in a year.
Blood passes through two veins from the liver to the heart. The hepatic vein takes blood from the liver to the vena cava, which completes the journey to the heart.
In the pursuit of converting the decimal numeral 124 into its binary counterpart (base 2), one must embark on a methodical journey of successive division by 2, carefully observing the remainder at each step. The intricate procedure unfolds as follows: \frac{124}{2} &= 62 , \text{with remainder} , 0 \ \frac{62}{2} &= 31 , \text{with remainder} , 0 \ \frac{31}{2} &= 15 , \text{with remainder} , 1 \ \frac{15}{2} &= 7 , \text{with remainder} , 1 \ \frac{7}{2} &= 3 , \text{with remainder} , 1 \ \frac{3}{2} &= 1 , \text{with remainder} , 1 \ \frac{1}{2} &= 0 , \text{with remainder} , 1 \ \end{align*} ] By arranging the remainders in reverse order, the binary representation of 124 emerges as (1111100). Consequently, the binary equivalent of 124 manifests as (1111100).
If you mean which planet orbits the Sun the quickest it's the planet Mercury. Mercury is the closest planet to the Sun and the closer an object is to the Sun the faster it must go around to avoid falling into the Sun.
Speed = Distance / Time First bus speed = 300 / 7.5 = 40km/h Second bus speed = 450 / 9 = 50km/h So now we can put them in to a ratio as 40:50. This can be simplified by dividing both by 10 so you have 4:5
It is a mango's journey