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Time in Distance 1+ time in distance 2= 22

let the 1st Distance be x

2nd Distance = 500-x

time = distance / speed

x/10 + (500-x)/50= 22

LCM = 50

multiply equation by 50

5x+500-x=1100

4x=600

x=150 m

150 m at 10m/s

350 m at 50m/s

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Q: A cyclist completes a journey of 500 meters in 22seconds part of the way at 10 meter per seconds and the remainder at 50 meter per second how far does she travel at each speed?
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